An orienteer runs 400m directly east and then 500m to the northeast (at a 45 degree andle from due east and from due north). Pro
vide a graphic solution to show final displacement with respect to the starting position
1 answer:
Answer:
Final displacement with respect to the starting position is 832.37 meter
Explanation:
Lets consider that the orienteer start to run on the point of (0,0) point of a coordinate system. When he runs towards to east side about 400m, he will be at the point A(400,0). After he runs to the northeast (at a 45 degree angle from due east and from due north), approximately he will make 353.55 meter to east and 353.55 meter to the north side and he will be at the point of B(753.55, 353.55)
From the starting point total displacement will be 832.37 meter. Please check the attached graphical solution.
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Answer:
from the above analysis we can say that the angular velocity in the later case is more than that of the former case. This means that the number of rotation made in the truck case is more than that made in pike position.
Explanation:
This can be explained on the basis of conservation of angular momentum.
This means the initial and the final angular velocity is conserved. Consider initial position (1)in the pike and final position in the be truck position. So there inertia's will also be different.
⇒
also,
since,
therefore,
So, from the above analysis we can say that the angular velocity in the later case is more than that of the former case. This means that the number of rotation made in the truck case is more than that made in pike position.
Answer:
= 7.02 ° C
Explanation:
The liquid water gives heat to melt the ice (Q₁) maintaining the temperature of 0 ° C and then the two waters are equilibrated to a final temperature.
Let's start by calculating the heat needed to melt the ice
Q₁ = m L
Q₁ = 0.090 3.33 10⁵
Q₁ = 2997 10⁴ J
This is the heat needed to melt all the ice
Now let's calculate at what temperature the water reaches when it releases this heat
Q = M (T₀ -
)
Q₁ = Q
= T₀ - Q₁ / M
= 20.0 - 2997 104 / (0.600 4186)
= 20.0 - 11.93
= 8.07 ° C
This is the temperature of the water when all the ice is melted
Now the two bodies of water exchange heat until they reach an equilibrium temperature
Temperatures are
Water of greater mass T₀₂ = 8.07ºC
Melted ice T₀₁ = 0ºC
M (T₀₂ -
) = m
(
- T₀₁)
M T₀₂ + m T₀₁ = m + M
= (M T₀₂ + 0) / (m + M)
= M / (m + M) T₀₂
let's calculate
= 0.600 / (0.600 + 0.090) 8.07
= 7.02 ° C