An orienteer runs 400m directly east and then 500m to the northeast (at a 45 degree andle from due east and from due north). Pro
vide a graphic solution to show final displacement with respect to the starting position
1 answer:
Answer:
Final displacement with respect to the starting position is 832.37 meter
Explanation:
Lets consider that the orienteer start to run on the point of (0,0) point of a coordinate system. When he runs towards to east side about 400m, he will be at the point A(400,0). After he runs to the northeast (at a 45 degree angle from due east and from due north), approximately he will make 353.55 meter to east and 353.55 meter to the north side and he will be at the point of B(753.55, 353.55)
From the starting point total displacement will be 832.37 meter. Please check the attached graphical solution.
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Answer:
46.4 s
Explanation:
5 minutes = 60 * 5 = 300 seconds
Let g = 9.8 m/s2. And be the slope of the road, s be the distance of the road, a be the acceleration generated by Rob, 3a/4 is the acceleration generated by Jim . Both of their motions are subjected to parallel component of the gravitational acceleration
Rob equation of motion can be modeled as s = a_Rt_R^2/2 = a300^2/2 = 45000a[/tex]
Jim equation of motion is
As both of them cover the same distance
So Jim should start 346.4 – 300 = 46.4 seconds earlier than Rob in other to reach the end at the same time
Answer:
14160 kg/m^3
Explanation:
First of all, we need to find the volume of the cylinder.
The volume of the cylinder is given by:
where:
is the radius
is the height
Substituting, we find
And the density is given by
where m = 1 kg is the mass. Substituting, we find