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BARSIC [14]
2 years ago
12

Identify the false statement: Select one:

Physics
2 answers:
svet-max [94.6K]2 years ago
8 0

Answer:

D) Synthesizers have always had a well-established presence in standard ensembles

Explanation:

As synthesizers are electronic music instruments that can create the sounds of many different musical instruments, they have been seen as a threat to many musicians since their invention.

Oxana [17]2 years ago
3 0

Answer:

<em>D) Synthesizers have always had a well-established presence in standard ensembles</em>

Explanation:

<h2>Question</h2>

Identify the false statement: Select one:

A) Synthesis refers to creating sounds electronically from electronically generated waveforms.

B) The synthesizer generates sounds electronically.

C) On the synthesizer, timbre and volume depend on the waveform.

D) Synthesizers have always had a well-established presence in standard ensembles.

A synthesizer is an electronic musical instrument that generates audio signals. Synthesizers generate audio through the following means: subtractive synthesis, additive synthesis, and frequency modulation synthesis. .

,they generate sounds electronically by the virtue of the oscillator

c. on the synthesizer , timbre and volume depend on the waveform , which is true

D is absolutely not correct

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A truck collides with a car on horizontal ground. At one moment during the collision, the magnitude of the acceleration of the t
Mice21 [21]

Answer:

The magnitude of the acceleration of the car is 35.53 m/s²

Explanation:

Given;

acceleration of the truck, a_t = 12.7 m/s²

mass of the truck, m_t = 2490 kg

mass of the car, m_c = 890 kg

let the acceleration of the car at the moment they collided = a_c

Apply Newton's third law of motion;

Magnitude of force exerted by the truck = Magnitude of force exerted by the car.

The force exerted by the car occurs in the opposite direction.

F_c = -F_t\\\\m_ca_c = -m_t a_t\\\\a_c =- \frac{m_ta_t}{m_c} \\\\a_c = -\frac{2490 \times 12.7}{890} \\\\a_c = - 35.53 \ m/s^2

Therefore, the magnitude of the acceleration of the car is 35.53 m/s²

3 0
2 years ago
Which of these is true of a chemical reaction? (a) energy is always transferred from reactants to products. (b) Energy is transf
lorasvet [3.4K]
The answer is B: energy is transferred, but it can go to the products or the reactants.
3 0
2 years ago
Read 2 more answers
A force of 5000 n is applied outwardly to each end of a 5.0-m long rod with a radius of 34.0 mm and a young's modulus of 125 x 1
Blizzard [7]
Por definicion tenemos que
 (F/A) = E(∆/0)
 Sustituyendo los valores tenemos y despejando ∆:
 ∆ = (F/(πr2 × E))*0
 (5000×5)/(3.14×(34×10^−2)^2×(125×10^8))
 5.5×10^−6 m
 
4 0
1 year ago
Read 2 more answers
a 1.2x10^3 kilogram car is accelerated uniformly from 10. meters per second to 20 meters per second in 5.0 seconds. what is the
irinina [24]
Force , F = ma

F =  m(v - u)/t               

Where m = mass in kg, v= final velocity in m/s, u = initial velocity in m/s
t = time, Force is in Newton.

m= 1.2*10³ kg,  u = 10 m/s,  v = 20 m/s, t = 5s

F =  1.2*10³(20 - 10)/5

F = 2.4*10³ N = 2400 N


7 0
1 year ago
A 600-turn solenoid, 25 cm long, has a diameter of 2.5 cm. A 14-turn coil is wound tightly around the center of the solenoid. If
Delvig [45]

Answer:

The induced emf in the short coil during this time is 1.728 x 10⁻⁴ V

Explanation:

The magnetic field at the center of the solenoid is given by;

B = μ(N/L)I

Where;

μ is permeability of free space

N is the number of turn

L is the length of the solenoid

I is the current in the solenoid

The rate of change of the field is given by;

\frac{\delta B}{\delta t} = \frac{\mu N \frac{\delta i}{\delta t} }{L} \\\\\frac{\delta B}{\delta t} = \frac{4\pi *10^{-7} *600* \frac{5}{0.6} }{0.25}\\\\\frac{\delta B}{\delta t} =0.02514 \ T/s

The induced emf in the shorter coil is calculated as;

E = NA\frac{\delta B}{\delta t}

where;

N is the number of turns in the shorter coil

A is the area of the shorter coil

Area of the shorter coil = πr²

The radius of the coil = 2.5cm / 2 = 1.25 cm = 0.0125 m

Area of the shorter coil = πr² = π(0.0125)² = 0.000491 m²

E = NA\frac{\delta B}{\delta t}

E = 14 x 0.000491 x 0.02514

E = 1.728 x 10⁻⁴ V

Therefore, the induced emf in the short coil during this time is 1.728 x 10⁻⁴ V

8 0
2 years ago
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