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Bumek [7]
1 year ago
14

A geologist is studying the shore along a river. She finds a pile of rocks at the base of a riverbank. These broken rock pieces

are the result of .
Physics
2 answers:
krok68 [10]1 year ago
4 0

erosion caused by the river flow

Sidana [21]1 year ago
4 0

A geologist is studying the shore along a river. She finds a pile of rocks at the base of a river bank. These broken rock pieces are the result of WEATHERING. A little farther along the river, the geologist find some smaller Pebbles and a very shallow, slow-moving section of the river. These rocks were moved to this location through the process of EROSION. The process of the Rocks actually being placed here it's called DEPOSITION

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A conveyer belt moves a 40 kg box at a velocity of 2 m/s. What is the kinetic energy of the box while it is on the conveyor belt
andrew-mc [135]
Kinetic energy =  \frac{mass*velocity ^{2} }{2} =  \frac{40*2 ^{2} }{2} = 80J. Therefore kinetic energy of the box while on the conveyor belt is 80J. 
4 0
1 year ago
Read 2 more answers
An engine performs 6400 j of work on a motorbike the motorbike and the rider have a combined mass of 200 kg if the bike started
spin [16.1K]

The work done by the engine is converted into kinetic energy of the motorbike+rider system:

W=K=\frac{1}{2}mv^2

where

W=6400 J is the work

m=200 kg is the mass of the system

v is the speed acquired by the motorbike


Rearranging the equation and substituting the numbers in, we find

v=\sqrt{\frac{2W}{m}} =\sqrt{\frac{2(6400 J)}{200 kg}} =8 m/s

4 0
1 year ago
Two long, parallel, current-carrying wires lie in an xy-plane. The first wire lies on the line y = 0.340 m and carries a current
sladkih [1.3K]

Answer:

The y-value of the line in the xy-plane where the total magnetic field is zero  U = 0.1355 \ m

Explanation:

From the question we are told that

    The distance of wire one from two along the y-axis is    y = 0.340 m

   The current on the first wire is  I_1 =  (27.5i) A

    The force per unit length on each wire is  Z =  295 \mu N/m = 295*10^{-6}  N/m

Generally the force per unit length is mathematically represented as

         Z = \frac{F}{l}  =  \frac{\mu_o I_1I_2}{2\pi y}

=>      \frac{\mu_o I_1I_2}{2\pi y}  =  295

Where  \mu_o is the permeability of free space with a constant value of  \mu_o  =  4\pi *10^{-7} \ N/A2

substituting values

       \frac{ 4\pi *10^{-7} 27.5 * I_2}{2\pi * 0.340}  =  295 *10^{-6}

=>    I_2 =  18.23 \ A

Let U  denote the  line in the xy-plane where the total magnetic field is zero

So  

      So the force per unit length of  wire 2  from  line  U is equal to the force per unit length of wire 1  from  line  (y - U)      

   So  

         \frac{\mu_o  I_2  }{2 \pi U} =  \frac{\mu_o  I_1  }{2 \pi(y -  U) }

substituting values

          \frac{  18.23  }{ U} =  \frac{ 27.5 }{(0.34 -  U) }

         6.198 -18.23U = 27.5U

          6.198=45.73U

          U = 0.1355 \ m              

5 0
1 year ago
Consider a double-slit with a distance between the slits of 0.04 mm and slit width of 0.01 mm. Suppose the screen is a distance
scZoUnD [109]

Answer:

The distance between the places where the intensity is zero due to the double slit effect is 15 mm.

Explanation:

Given that,

Distance between the slits = 0.04 mm

Width = 0.01 mm

Distance between the slits and screen = 1 m

Wavelength = 600 nm

We need to calculate the distance between the places where the intensity is zero due to the double slit effect

For constructive fringe

First minima from center

x_{1}=\dfrac{\lambda D}{2d}

Second minima from center

x_{2}=\dfrac{3\lambda D}{2d}

The distance between the places where the intensity is zero due to the double slit effect

\Delta x_{d}=x_{2}-x_{1}

\Delta x_{d}=\dfrac{3\lambda D}{2d}-\dfrac{\lambda D}{2d}

\Delta x_{d}=\dfrac{\lambda D}{d}

Put the value into the formula

\Delta x_{d}=\dfrac{600\times10^{-9}\times1}{0.04\times10^{-3}}

\Delta x_{d}=0.015 =15\times10^{-3}\ m

\Delta x_{d}=15\ mm

Hence, The distance between the places where the intensity is zero due to the double slit effect is 15 mm.

8 0
2 years ago
Two identical stunt professionals A and B stand on the roof of building 1. Person A steps off of the roof and falls vertically o
Vladimir [108]

Answer:

Both of the stunt professionals will sustain injuries of the same seriousness

Explanation:

We are being told that both stunt professionals are standing from the same height, therefore they will attain the same  equivalent speed at the bottom if we are to look at it from the principle of conservation of energy.

Now; According to principle of momentum; the momentum at which the first stunt professional A hits the ground be equal as the momentum with which stunt professional B will hit the wall.

Thus; both of the stunt professionals will sustain injuries of the same seriousness

6 0
1 year ago
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