The work done by the engine is converted into kinetic energy of the motorbike+rider system:

where
W=6400 J is the work
m=200 kg is the mass of the system
v is the speed acquired by the motorbike
Rearranging the equation and substituting the numbers in, we find
Answer:
The y-value of the line in the xy-plane where the total magnetic field is zero 
Explanation:
From the question we are told that
The distance of wire one from two along the y-axis is y = 0.340 m
The current on the first wire is 
The force per unit length on each wire is 
Generally the force per unit length is mathematically represented as

=> 
Where
is the permeability of free space with a constant value of 
substituting values

=>
Let U denote the line in the xy-plane where the total magnetic field is zero
So
So the force per unit length of wire 2 from line U is equal to the force per unit length of wire 1 from line (y - U)
So

substituting values



Answer:
The distance between the places where the intensity is zero due to the double slit effect is 15 mm.
Explanation:
Given that,
Distance between the slits = 0.04 mm
Width = 0.01 mm
Distance between the slits and screen = 1 m
Wavelength = 600 nm
We need to calculate the distance between the places where the intensity is zero due to the double slit effect
For constructive fringe
First minima from center

Second minima from center

The distance between the places where the intensity is zero due to the double slit effect



Put the value into the formula



Hence, The distance between the places where the intensity is zero due to the double slit effect is 15 mm.
Answer:
Both of the stunt professionals will sustain injuries of the same seriousness
Explanation:
We are being told that both stunt professionals are standing from the same height, therefore they will attain the same equivalent speed at the bottom if we are to look at it from the principle of conservation of energy.
Now; According to principle of momentum; the momentum at which the first stunt professional A hits the ground be equal as the momentum with which stunt professional B will hit the wall.
Thus; both of the stunt professionals will sustain injuries of the same seriousness