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LiRa [457]
2 years ago
12

Three identical 50-kg balls are held at the corners of an equilateral triangle, 30 cm on each side. if one of the balls is relea

sed, what is the magnitude of its initial acceleration if the only forces acting on it are the gravitational forces due to the other two masses? (g = 6.67 × 10-11 n • m2/kg2)
Physics
2 answers:
Ivahew [28]2 years ago
6 0

Answer:

a= 6.42×10⁻⁸m/s²

Explanation:

Given Data

mass=m=50 kg

angle=α=30°

Gravitational Constant=G=6.67 × 10-11 Nm²/kg²)

To find

acceleration=a=?

Solution

From Gravitational Law " the force of attraction between all masses in the universe; especially the attraction of the earth's mass for bodies near its surface "

F₁ = G×m²/D²

F = 2*F₁*cos30° = 2*G*50²*cos30°/0.3² = 3.21×10⁻⁶N  

a = F/m = 3.21×10⁻⁶/50

a= 6.42×10⁻⁸m/s²

natima [27]2 years ago
3 0
F1 = G*m²/D² 
<span>F = 2*F1*cos30° = 2*G*50²*cos30°/0.3² = 3.21E-6 </span>

<span>a = F/m = 3.21E-6/50 = 6.42E-8

Hope this helped!
STSN</span>
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