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saul85 [17]
2 years ago
14

The homeowner installs an electrically heated mirror into the shower room.When a person has a shower, the heated mirrors does no

t become misty but stays clear.
Why does the mirror stay clear?
Physics
2 answers:
UkoKoshka [18]2 years ago
8 0
When you have a warm shower, you create steam. So when the warm steam flows in the air and starts to be in contact with a cold surface, it condenses causing a mist to form on the cold surface. The heated mirror is warm so, when, the steam is in contact with the mirror condensation is prevented. Therefore, the mirror stays clear.
Scrat [10]2 years ago
8 0
Cause the only reason a mirror becomes misty when you take a shower is because the steam from the water rises and then condenses on the cold surface of the mirror cause it cools down the steam back to it's origional form of water. But if you had a heated mirror the steam wouldn't condense back to water when it touched the mirror so the mirror stays clear:)    
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What type of equilibrium is guaranteed by each condition of equilibrium
Ostrovityanka [42]

Answer: Conditions for equilibrium require that the sum of all external forces acting on the body is zero (first condition of equilibrium), and the sum of all external torques from external forces is zero (second condition of equilibrium). These two conditions must be simultaneously satisfied in equilibrium

Explanation: Hope this helped

5 0
2 years ago
A couch is pushed with a horizontal force of 80 N and moves the couch a
Lapatulllka [165]

Answer:

400 J

Explanation:

Work = force × distance

W = (80 N) (5 m)

W = 400 J

5 0
2 years ago
Read 2 more answers
Carts A and B are identical and are moving toward each other on a track. The speed of cart A is v, while the speed of cart B is
borishaifa [10]

Answer: k= \frac{5mv^{2} }{2}

Explanation:

Recall that the formula for kinetic energy is given below as

k = \frac{mv^{2} }{2}

where k=kinetic energy (joules), m= mass of object (kg), v= velocity of object m/s)

For cart A

m_{a} = mass of cart A

v_{a} = v = velocity of cart A

K.E_{a} = kinetic energy of cart A

hence, K.E_{a} = \frac{m_{a}v^{2}  }{2}

For cart B

m_{b} = mass of cart B

v_{b} = 2v = velocity of cart B

K.E_{b} = kinetic energy of cart B

hence, K.E_{b} = \frac{m_{b}(2v^{2}) }{2} = 2m_{b} v^{2}

from the question, both cart are identical which implies they have the same mass i.e m_{a} = m_{b} = m which implies that

K.E_{a}= \frac{mv^{2} }{2} and K.E_{b}  =2mv^{2}

The total kinetic energy K is the sum of cart A and cart B kinetic energy

K=K.E_{a} + K.E_{b}

K=\frac{mv^{2} }{2} + 2mv^{2}

hence

K=\frac{5mv^{2} }{2}

6 0
2 years ago
A 12.0 kg mass, fastened to the end of an aluminum wire with an unstretched length of 0.50 m, is whirled in a vertical circle wi
Kamila [148]

Answer:

A.)1.52cm

B.)1.18cm

Explanation:

angular speed of 120 rev/min.

cross sectional area=0.14cm²

mass=12kg

F=120±12ω²r

=120±12(120×2π/60)^2 ×0.50

=828N or 1068N

To calculate the elongation of the wire for lowest and highest point

δ=F/A

= 1068/0.5

δ=2136MPa

'E' which is the modulus of elasticity for alluminium is 70000MPa

δ=ξl=φl/E =2136×50/70000=1.52cm

δ=F/A=828/0.5

=1656MPa

δ=ξl=φl/E

=1656×50/70000=1.18cm

δ=1.18cm

6 0
2 years ago
Read 2 more answers
A vertical spring of constant k = 400 N/m hangs at rest. When a 2 kg mass is attached to it, and it is released, the spring exte
Viefleur [7K]

Answer:

4.9 cm

Explanation:

From Hook's Law,

F = ke......................... Equation 1

Where F= force, e = extension, k = spring constant.

Note: the Force acting on the the spring is the weight of the mass.

W = mg.

F = mg.................... Equation 2

Where m = mass, g = acceleration due to gravity

Substitute equation 2 into equation 1

mg = ke

make e the subject of the equation

e = mg/k............... Equation 3.

Given: m = 2 kg, g = 9.8 m/s², k = 400 N/m

e = (2×9.8)/400

e = 19.6/400

e = 0.049 m

e = 4.9 cm

3 0
2 years ago
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