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Andru [333]
2 years ago
10

You and your surfing buddy are waiting to catch a wave a few hundred meters off the beach. The waves are conveniently sinusoidal

, and you notice that when you're on the top of one wave and moving toward your friend, she is exactly halfway between you and the trough of the wave. 1.50 seconds later, your friend is at the top of the wave. You estimate the horizontal distance between you and your friend at 8.00 m. (a) What is the frequency of the waves?

Physics
2 answers:
Nata [24]2 years ago
8 0

(a) The frequency of the waves is ¹/₆ Hz ≈ 0.167 Hz

(b) The speed of the waves is 5¹/₃ m/s ≈ 5.33 m/s

\texttt{ }

<h3>Further explanation</h3>

Let's recall the speed of wave and intensity of wave formula as follows:

\large {\boxed {v = \lambda f}}

<em>f = frequency of wave ( Hz )</em>

<em>v = speed of wave ( m/s )</em>

<em>λ = wavelength ( m )</em>

\texttt{ }

\large {\boxed {I = 2 \pi^2 A^2 f^2 \rho v}}

<em>I = intensity of wave ( W/m² )</em>

<em>A = amplitude of wave ( m )</em>

<em>f = frequeny of wave ( Hz )</em>

<em>ρ = density of medium ( kg/m³ )</em>

<em>v = speed of wave ( m/s )</em>

<em>Let's tackle the problem!</em>

\texttt{ }

<u>Given:</u>

time taken = t = 1.50 seconds

distance covered = d = 8.00 m

<u>Asked:</u>

(a) frequency of the waves = ?

(b) speed of the waves = ?

<u>Solution:</u>

<h3>Question (a):</h3>

t = \frac{1}{4}T

1.50 = \frac{1}{4}T

T = 4 \times 1.50

T = 6 \texttt{ seconds}

\texttt{ }

f = \frac{1}{T}

f = \frac{1}{6} \texttt{ Hz}

\texttt{ }

<h3>Question (b):</h3>

d = \frac{1}{4}\lambda

8.00 = \frac{1}{4}\lambda

\lambda = 8.00 \times 4

\lambda = 32 \texttt{ m}

\texttt{ }

v = \lambda f

v = 32 \times \frac{1}{6}

v = 5\frac{1}{3} \texttt{ m/s}

\texttt{ }

<h3>Learn more</h3>
  • Doppler Effect : brainly.com/question/3841958
  • Example of Doppler Effect : brainly.com/question/810552
  • Sound Waves Cannot Travel In Space. : brainly.com/question/546436
  • Frequency of The Beats - Doppler Effect : brainly.com/question/12367463

\texttt{ }

<h3>Answer details</h3>

Grade: College

Subject: Physics

Chapter: Sound Waves

bekas [8.4K]2 years ago
6 0

Answer:

(a): The frequency of the waves is f= 0.16 Hz

Explanation:

T/4= 1.5 s

T= 6 sec

f= 1/T

f= 0.16 Hz (a)

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Answer:

Explanation:

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If I assume that the wind move the plane:

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7. A local sign company needs to install a new billboard. The signpost is 30 m tall, and the ladder truck is parked 24 m away fr
wolverine [178]
<h2>Solution :</h2>

Here ,

• Height of sign post = 30 m

• Distance between signpost and truck = 24 m

Let the

• Top of signpost = A

• Bottom of signpost = B

• The end of truck facing sign post be = C

Now as we can clearly imagine that the ladder will act as an hypotenuse to the Triangle ABC .

Where

• AB = Height of signpost = 30 m

• BC = distance between both = 24 m

• AC = Minimum length of ladder

→ AC² = AB² + BC² ( As we can see AB is perpendicular to BC )

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→ AC² = 900 + 576

→ AC² = 1476

→ AC = 38.41875

or AC apx = 38.42

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A tennis ball of mass m=0.060 kg and speed v=25 m/s strikes a wall at a 45 angle and rebounds with the same velocity at 45°. Wha
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