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Anastaziya [24]
2 years ago
15

A dragster crosses the finish line with a velocity of 140m/s . Assuming the vehicle maintained a constant acceleration from star

t to finish, what was its average velocity for the race?

Physics
1 answer:
Mumz [18]2 years ago
5 0

Answer:

Answer is attached

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Now suppose the initial velocity of the train is 4 m/s and the hill is 4 meters tall. If the train has a mass of 30000 kg, what
hoa [83]

Answer:

<h2>187,500N/m</h2>

Explanation:

From the question, the kinectic energy of the train will be equal to the energy stored in the spring.

Kinetic energy = 1/2 mv² and energy stored in a spring E = 1/2 ke².

Equating both we will have;

1/2 mv² = 1/2ke²

mv² = ke²

m is the mass of the train

v is the velocity of then train

k is the spring constant

e is the extension caused by the spring.

Given m = 30000kg, v = 4 m/s, e = 4 - 2.4 = 1.6m

Substituting this values into the formula will give;

30000*4² =  k*1.6²

k = \frac{30,000*16}{1.6^2}\\ \\k = \frac{480,000}{2.56}\\ \\k = 187,500Nm^{-1}

The value of the spring constant is 187,500N/m

7 0
2 years ago
Suppose an X-ray binary is found in which the visible star is a 12 M⦿ red giant, the orbital period is 3.65 days, and the semima
nataly862011 [7]

Answer:

If the mass of a star is greater than 3 solar masses, it will create a black hole. If its mass is less, it will create a neutron star.

Explanation:

If a star's gravity is high enough, when it condenses on itself, it will form a black hole. Otherwise, it will create a large amount of highly dense matter, such as a neutron star. It can be said that if the mass of a star is greater than 3 solar masses, it will create a black hole. If its mass is less, it will create a neutron star.

8 0
2 years ago
A pulley 12 cm in diameter is free to rotate about a horizontal axle. A 220-g mass and a 470-g mass are tied to either end of a
Aleks [24]

Answer:0.147 N-m

Explanation:

Given

Diameter of Pulley d=12 cm

radius r=6 cm

mass of first object m_1=220 gm

mass of second object m_2=470 gm

Now both masses will exert a torque a on Pulley

Torque due to first Pulley T_1=m_1g\cdot r

T_1=0.22\times 9.8\times 0.06=0.129 N-m

Torque due to second mass on Pulley T_2=m_2g\cdot r

T_2=0.276 N-m

Total Torque by masses T_{net}=T_2-T_1

T_{net}=0.276-0.129=0.147 N-m

so we need to apply a torque of magnitude 0.147 N-m opposite to the direction of T_{net}  

3 0
2 years ago
Which objects have both potential and kinetic energy? Check all that apply.
wariber [46]
A falling raindrop
Kinetic energy and potential energy are both applied when a body or object is falling.
3 0
2 years ago
Read 2 more answers
A soccer ball kicked with a force of 13.5 n accelerates at 6.5 m/s^2 to the right. what is the mass of the ball?
Art [367]

Answer:

2.08 kg

Explanation:

We can solve the problem by using Newton's second law:

F=ma

where

F is the net force acting on an object

m is the mass of the object

a is its acceleration

In this problem, the ball is kicked with a force of F=13.5 N, and its acceleration is a=6.5 m/s^2, therefore we can re-arrange the equation to find the mass of the ball, m:

m=\frac{F}{a}=\frac{13.5 N}{6.5 m/s^2}=2.08 kg

7 0
2 years ago
Read 2 more answers
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