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2 years ago

A soccer ball kicked with a force of 13.5 n accelerates at 6.5 m/s^2 to the right. what is the mass of the ball?

Physics

2 answers:

Art [367]2 years ago

7 0

Answer:

2.08 kg

Explanation:

We can solve the problem by using Newton's second law:

$F=ma$

where

F is the net force acting on an object

m is the mass of the object

a is its acceleration

In this problem, the ball is kicked with a force of F=13.5 N, and its acceleration is a=6.5 m/s^2, therefore we can re-arrange the equation to find the mass of the ball, m:

$m=\frac{F}{a}=\frac{13.5 N}{6.5 m/s^2}=2.08 kg$

STatiana [176]2 years ago

4 0

Answer: The mass of an ball is 2.08 kg.

Explanation:

Force is defined as the push or pull on an object with some mass that causes change in its velocity.

It is also defined as the mass multiplied by the acceleration of the object.

Mathematically,

$F=m\times a$

where,

F = force exerted on the ball = 13.5 N

m = mass of the ball = ?

a = acceleration of the ball = $6.5m/s^2$

Putting values in above equation, we get:

$13.5kg.m/s^2=m\times 6.5m/s^2\\\\m=\frac{13.5}{6.5}=2.08kg$

Hence, the mass of an object is 2.08 kg

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The constant pressure molar heat capacity, C_{p,m}C p,m , of nitrogen gas, N_2N 2 , is 29.125\text{ J K}^{-1}\text{ mol}^{-1

antoniya [11.8K]

Answer:

Explanation:

Constant pressure molar heat capacity Cp = 29.125 J /K.mol

If Cv be constant volume molar heat capacity

Cp - Cv = R

Cv = Cp - R

= 29.125 - 8.314 J

= 20.811 J

change in internal energy = n x Cv x Δ T

n is number of moles , Cv is molar heat capacity at constant volume , Δ T is change in temperature

Putting the values

= 20 x 20.811 x 15

= 6243.3 J.

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2 years ago

Compressional stress on rock can cause strong and deep earthquakes, usually at _____.

valentinak56 [21]

The answer is reverse faults.

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A square block of steel with volume 10 cm3 and mass of 75 g is cut precisely in half. The density of the two smaller pieces is n

dem82 [27]

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2 years ago

Read 2 more answers

Whale sharks swim forward while ascending or descending. They swim along a straight-line path at a shallow angle as they move fr

Aneli [31]

You did not include the quesetion, but I can help you to understand the problem and how to find the relevant information.

1) The angle of 13° with which the shark ascends meets this:

Vertical ascending velocity = 0.85m/s * sin(13°)

Horizontal velocity = 0.85m/s * cos(13°)

2) The length swan by the shark ascending meets this

Vertical ascending length = 50 m

Horizontal length, y:

$\frac{y}{50} = \frac{0.85sin(13)}{0.85cos(13)}$

From that y = 50 * tan(13°)

=> y = 11.54 m.

3) Conclusions:

1) The shark run 50 m vertically upward and 11.54 m horizontally.

2) The length of the path run by the shark may be calculated using Pythagoras' theorem:

hypotenuse^2 = (50m)^2 + (11.54m)^2 = 2633.25m^2

hypotenuse = 51.35m

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4 0

2 years ago

Which of the following statements is FALSE?

Levart [38]

A thrust fault is a reverse fault with an extremely high dip (close to 90°). This is the false statement.

Answer: Option D

Explanation:

Faults are the fracture or fracture zone occurring on the rocks. These fractures can travel through the rocks leading to massive destruction. So, depending upon the direction of their travel, the faults can be classified as normal, reverse and strike slip fault. Also, the angle of dip along the fault is one of the important criteria for determining the type of faults.

There is dip-slip fault which has its movement along the vertical fault plane while the strike slip fault will be in horizontal direction. Similarly, an oblique fault will be acting in both vertical and the horizontal direction. So, the fourth statement related to thrust fault is false as in reverse fault or thrust fault the dip will be shallow and not high.

5 0

2 years ago