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mart [117]
2 years ago
6

A square block of steel with volume 10 cm3 and mass of 75 g is cut precisely in half. The density of the two smaller pieces is n

ow...
a. the same as the original density.
b. one-half the original density.
c. two times the original density.
d. one-fourth the original density.
Physics
2 answers:
Ann [662]2 years ago
5 0

Answer:

a. the same as the original density.

Explanation:

The density of a material depends only on the properties of the material, so if a block of steel is cut in a half, it is still made of the same material (steel), so it still has the same density.

We can verify it by doing some calculations. In fact, the initial density of the block of steel is given by the ratio between its mass (75 g) and its volume (10 cm^3):

d=\frac{m}{V}=\frac{75 g}{10 cm^3}=7.5 g/cm^3

When the block is cut in a half, its mass becomes half:

m' = \frac{m}{2}=\frac{75 g}{2}=37.5 g

and its volume also becomes half:

V'=\frac{V}{2}=\frac{10 cm^3}{2}=5 cm^3

So the new density is

d'=\frac{m'}{V'}=\frac{37.5 g}{5 cm^3}=7.5 g/cm^3

So, the density has not changed.

dem82 [27]2 years ago
4 0
A. Density only depends on the substance. It doesn't matter whether you have a little chip of it or a supertanker full of it ... the density doesn't change.
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klio [65]

Answer:

57.94°

Explanation:

we know that the expression of flux

\Phi =E\times S\times COS\Theta

where Ф= flux

           E= electric field

           S= surface area

        θ = angle between the direction of electric field and normal to the surface.

we have Given Ф= 78 \frac{Nm^{2}}{sec}

                          E=1.44\times 10^{4}\frac{Nm}{C}

                          S=\pi \times 0.057^{2}

                         COS\Theta =\frac{\Phi }{S\times E}

 =   \frac{78}{1.44\times 10^{4}\times \pi \times 0.057^{2}}

 =0.5306

 θ=57.94°

4 0
2 years ago
Rank the following situations according to the magnitude of the impulse of the net force, from largest value to smallest value.
wolverine [178]

Answer:

V

I and II

III and IV

Explanation:

The impulse is equal to the change in momentum of the object involved, so we can calculate the change in momentum in each situation and compare them all.

Taking always east as positive direction, and labelling

u the initial velocity

v the final velocity

m = 1000 kg the mass (which is always equal)

We find:

(i)

u = 25 m/s

v = 0

|I|=m(v-u)=(1000)(0-25)=25,000 Ns

(II)

u = 25 m/s

v = 0

|I|=m(v-u)=(1000)(0-25)=25,000 Ns

(III)

In this case,

F = 2000 N is the force

\Delta t = 10 s is the time

So the magnitude of the impulse is

|I| =F\Delta t = (2000N)(10)=20,000 Ns

(IV)

F = 2000 N is the force

\Delta t = 10 s is the time

So the magnitude of the impulse is

|I| =F\Delta t = (2000N)(10)=20,000 Ns

(V)

u = 25 m/s

v = -25 m/s

|I|=m(v-u)=(1000)(-25-25)=50,000 Ns

So the ranking from largest to smallest is:

V

I and II

III and IV

5 0
2 years ago
1. A liquid of mass 250g is heated with an electric heater. Its temperature rises from 30°C to 80°C, the specific heat capacity
statuscvo [17]

Answer:

1) 50 seconds 2) 100°C

Explanation:

(Follows formula of Power=Energy/Time)

1) 500W x X = 2000J/kg°C x .25kg x 50°C

X = 50 seconds.

2) 2000W x 300s = 1000J/kg°C x 2kg x X

X = 300

Initial temperature => 400°C-300°C = 100°C

8 0
2 years ago
A uniform cube with mass 0.700 kg and volume 0.0270 m3 is sitting on the floor. A uniform sphere with radius 0.400 m and mass 0.
Sav [38]

Answer:

  44 1/3 cm

Explanation:

The cube has an edge length of ∛0.027 m = 0.3 m, so a center of mass (CoM) 15 cm above the floor.

The sphere's center of mass is 40 cm above the top of the cube, so is 70 cm above the floor. The weighted average of the CoM locations is ...

  ((15 cm)(0.700 kg) +(70 cm)(0.800 kg))/(0.700 kg +0.800 kg)

  = (10.5 kg·cm +56 kg·cm)/(1.500 kg) = 44.333... cm

The center of mass of the two-object system is 44 1/3 cm above the floor.

_____

<em>Comment on the units</em>

We're not familiar with "hcm" as a unit. We presume that you can convert the given answer to the units you desire.

6 0
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Zigmanuir [339]

Answer:

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Explanation:

<u>Focus groups</u>

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Exploratory methods are used to gain initial insights that could pave the way for further investigation.

Some of the exploratory methods are focus groups, Key informant,case studies,secondary data and observational data.

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2 years ago
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