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Vinvika [58]
2 years ago
7

Every spring has an equilibrium position. Which statements describe a spring at its equilibrium position? Check all that

Physics
2 answers:
alexgriva [62]2 years ago
8 0

Answer:

The elastic potential energy is zero.

The net force acting on the spring is zero.

Explanation:

The equilibrium position of a spring is the position that the spring has when its neither compressed nor stretched - it is also called natural length of the spring.

Let's now analyze the different statements:

The spring constant is zero.  --> false. The spring constant is never zero.

The elastic potential energy is at a maximum  --> false. The elastic potential energy of a spring is given by

E=\frac{1}{2}kx^2

where k is the spring constant and x the displacement. Therefore, the elastic potential energy is maximum when x, the displacement, is maximum.

The elastic potential energy is zero.  --> true. As we saw from the equation above, the elastic potential energy is zero when the displacement is zero (at the equilibrium position).

The displacement of the spring is at a maxi num  --> false, for what we said above

The net force acting on the spring is zero. --> true, as the spring is neither compressed nor stretched

Umnica [9.8K]2 years ago
7 0

Answer:

the person from above is correct

Explanation:

i just took the quiz

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Which of the following best describes a capacitor?
galben [10]

Answer:

B

Explanation:

The capacitor is a component which has the ability to store energy in the form of an electrical charge  making a potential difference on those two metal plates

A capacitor consists of two or more parallel conductive (metal) plates. They are electrically seperated by an insulating material (ex: air, mica,ceramic etc.) which is called as Dielectric Layer

Due to this insulating layer, DC current can not flow through the capacitor.But it allows a voltage to be present across the plates in the form of an electrical charge.

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Before you start taking measurements though, we’ll first make sure you understand the underlying concepts involved. By what meth
Svetradugi [14.3K]

Answer:

If they are metallic spheres  they are connected to earth and a charged body approaches

non- metallic (insulating) spheres in this case are charged by rubbing

Explanation:

For fillers, there are two fundamental methods, depending on the type of material.

If they are metallic spheres, they are connected to earth and a charged body approaches, this induces a charge of opposite sign and of equal magnitude, then it removes the contact to earth and the sphere is charged.

If the non- metallic (insulating) spheres in this case are charged by rubbing with some material or touching with another charged material, in this case the sphere takes half the charge and when separated each sphere has half the charge and with equal sign.

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2 years ago
This is really urgent
hodyreva [135]

20) When light passes from air to glass and then to air

21) When a light ray enters a medium with higher optical density, it bends towards the normal

22) Index of refraction describes the optical density

23) Light travels faster in the material with index 1.1

24) Glass refracts light more than water

25) Index of refraction is n=\frac{c}{v}

26) Critical angle: [tex]sin \theta_c = \frac{n_2}{n_1}[/tex]

27) Critical angle is larger for the glass-water interface

Explanation:

20)

It is possible to slow down light and then speed it up again by making light passing from a medium with low optical density (for example, air) into a medium with higher optical density (for example, glass), and then make the light passing again from glass to air.

This phenomenon is known as refraction: when a light wave crosses the interface between two different mediums, it changes speed (and also direction). The speed decreases if the light passes from a medium at lower optical density to a medium with higher optical density, and viceversa.

21)

The change in direction of light when it passes through the boundary between two mediums is given by Snell's law:

n_1 sin \theta_1 = n_2 sin \theta_2

with

n_1, n_2 are the refractive index of 1st and 2nd medium

\theta_1, \theta_2 are the angle of incidence and refraction (the angle between the incident ray (or refracted ray) and the normal to the boundary)

The larger the optical density of the medium, the larger the value of n, the smaller the angle: so, when a light ray enters a medium with higher optical density, it bends towards the normal.

22)

The index of refraction describes the optical density of a medium. More in detail:

  • A high index of refraction means that the material has a high optical density, which means that light travels more slowly into that medium
  • A low index of refraction means that the material has a low optical density, which means that light travels faster into that medium

Be careful that optical density is a completely different property from density.

23)

As we said in part 22), the index of refraction describes the optical density of a medium.

In this case, we have:

  • A material with refractive index of 1.1
  • A material with refractive index of 2.2

As we said previously, light travels faster in materials with a lower refractive index: therefore in this case, light travels more quickly in material 1, which has a refractive index of only 1.1, than material 2, whose index of refraction is much higher (2.2).

24)

Rewriting Snell's law,

sin \theta_2 = \frac{n_1}{n_2}sin \theta_1 (1)

For light moving from air to water:

n_1 \sim 1.00 is the index of refraction of air

n_2 = 1.33 is the index of refraction ofwater

In this case, \frac{n_1}{n_2}=\frac{1.00}{1.33}=0.75

For light moving from air to glass,

n_2 = 1.51 is the index of refraction of glass

And so

\frac{n_1}{n_2}=\frac{1.00}{1.51}=0.66

From eq.(1), we see that the angle of refraction \theta_2 is smaller in the 2nd case: so glass refracts light more than water, because of its higher index of refraction.

25)

The index of refraction of a material is

n=\frac{c}{v}

c is the speed of light in a vacuum

v is the speed of light in the material

So, the index of refraction is inversely proportional to the speed of light in the material:

  • The higher the index of refraction, the slower the light
  • The lower the index of refraction, the faster the light

26)

From Snell's law,

sin \theta_2 = \frac{n_1}{n_2}sin \theta_1

We notice that when light moves from a medium with higher refractive index to a medium with lower refractive index, n_1 > n_2, so \frac{n_1}{n_2}>1, and since sin \theta_2 cannot be larger than 1, there exists a maximum value of the angle of incidence \theta_c (called critical angle) above which refraction no longer occurs: in this case, the incident light ray is completely reflected into the original medium 1, and this phenomenon is called total internal reflection.

The value of the critical angle is given by

sin \theta_c = \frac{n_2}{n_1}

For angles of incidence above this value, total internal reflection occurs.

27)

Using:

sin \theta_c = \frac{n_2}{n_1}

For the interface glass-air,

n_1 \sim 1.51\\n_2 = 1.00

The critical angle is

\theta_c = sin^{-1}(\frac{n_2}{n_1})=sin^{-1}(\frac{1.00}{1.51})=41.5^{\circ}

For the interface glass-water,

n_1 \sim 1.51\\n_2 = 1.33

The critical angle is

\theta_c = sin^{-1}(\frac{n_2}{n_1})=sin^{-1}(\frac{1.33}{1.51})=61.7^{\circ}

So, the critical angle is larger for the glass-water interface.

Learn more about refraction:

brainly.com/question/3183125

brainly.com/question/12370040

#LearnwithBrainly

7 0
2 years ago
(d) A beam of white light shines onto a sheet of white paper. An identical beam of light shines onto a mirror. The light is scat
irakobra [83]
QUESTION:-A beam of white light shines onto a sheet of white paper. An identical beam of light shines onto a mirror. The light is scattered from the paper and reflected from the mirror.
Describe how scattering by paper and reflection by a mirror are different from each other.


ANSWER: Scattering sends or reflects light from each point on the object in all directions, whereas reflection sends light from each point on the object in one direction only (or to one point)
5 0
2 years ago
Where do incident rays that are parallel to the principal axis converge to after reflecting off a concave mirror?
morpeh [17]

Answer:

At focus

Explanation:

A concave mirror is converging in nature. In a mirror, concave in nature, the rays which are parallel to the principal axis are supposed to be coming from very large distances or we assume the source to be placed at infinity for such rays which are parallel to the principal axis.

These rays,  parallel to the principal axis, coming from infinity, converges at the focus of the mirror concave in nature after reflecting from the concave mirror

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