1) weight of the box: 980 N
The weight of the box is given by:

where m=100.0 kg is the mass of the box, and
is the acceleration due to gravity. Substituting in the formula, we find

2) Normal force: 630 N
The magnitude of the normal force is equal to the component of the weight which is perpendicular to the ramp, which is given by

where W is the weight of the box, calculated in the previous step, and
is the angle of the ramp. Substituting, we find

3) Acceleration: 
The acceleration of the box along the ramp is equal to the component of the acceleration of gravity parallel to the ramp, which is given by

Substituting, we find

Answer:
The amount of charge the space shuttle collects is -1.224nC
Explanation:
The magnitude of Electric potential is given as;
V = kq/r
where;
V is the electric potential in volts
k is coulomb's constant
r is the radius of the sphere or distance moved by the charge
given; V = -1.1 V, k = 8.99 x 10⁹ Nm²/C², r = 10m
Substituting this values in the above equation, we estimate the amount of charge space shuttle collects.
q = (V*r)/k
q = (-1.1 *10)/(8.99 x 10⁹ )
q = -1.224 X 10⁻⁹ C
q = -1.224nC
Therefore, the amount of charge the space shuttle collects is -1.224nC
Answer:
1.23917 m
0.14323 s
Explanation:
v = Speed of sound in dry air at 20 °C = 343.5 m/s
f = Frequency of note C# = 277.2 /s = 277.2 Hz
λ = Wavelength

Wavelength = 1.23917 m
Distance the wave needs to travel is 49.2 m
Time = Distance / Speed

Time taken for the sound to travel across the concert hall is 0.14323 s
Answer:
0.0367
Explanation:
The loss in kinetic energy results into work done by friction.
Since kinetic energy is given by
KE=0.5mv^{2}
Work done by friction is given as
W= umgd
Where m is the mass of suitacase, v is velocity of the suitcase, g is acceleration due to gravity, d is perpendicular distance where force is applied and u is coefficient of kinetic friction.
Making u the subject of the formula then we deduce that

Substituting v with 1.2 m/s, d with 2m and taking g as 9.81 m/s2 then

Therefore, the coefficient of kinetic friction is approximately 0.0367
Answer:
Mass of another particle, m = 46 kg
Explanation:
it is given that,
Mass of first particle, m₁ = 28 kg
Gravitational force, 
Distance between the particles, d = 3.2 m
We need to find the mass m of another particle. It is given by the formula as follows :



m = 45.5 kg
or
m = 46 kg
So, the correct option is (d) "46 kg". Hence, this is the required solution.