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andriy [413]
2 years ago
12

In this experiment, you need to examine the idea of thermal energy transfer. Using a controlled experiment, what might a good qu

estion about the variables that affect thermal energy transfer be? Thermal energy transfer depends on many properties, but limit your question to only two.
Physics
3 answers:
Rama09 [41]2 years ago
7 0

Answer:

We shall consider two properties:

1. Temperature difference

2. Thermal conductivity of the material

Use a cylindrical rod of a given material (say steel) which is insulated around its circumference.

One end of the rod is dipped in a large reservoir of water at 100 deg.C and the other end is dipped in water (with known volume) at 40 deg. C. The cold water if stored in a cylinder which is insulated on all sides. A thermometer reads the temperature of the cold water as a function of time.

This experiment will show that

(a) heat flows from a region of high temperature to a region of lower temperature.

(b) The thermal energy of a body increases when heat is added to it, and its temperature will rise.

(c) The thermal conductivity of water determines how quickly its temperature will rise. If mercury replaces water in the cold cylinder, its temperature will rise at a different rate because its thermal conductivity is different.

Explanation:

USPshnik [31]2 years ago
5 0

Answer:

the effect would be 2w=btyh,3

Explanation:

Guest2 years ago
0 0

answer: How do mass and the type of material affect thermal energy transfer
on edg its right

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Question 8 (4 points)
katrin2010 [14]

Answer:

The answer to your question is:

Explanation:

Data

Duane                                          Albert

d = 5 m ;  v = 3 m/s                     v = 4.2 m/s

a)                                                b)

Duane's                                      Albert's

d = 5 + (3)t                                  d = 4.2t

d = 5 + 3t

c)                            5 + 3t = 4.2t

                              4.2t - 3t = 5

                                      1.2t = 5

                                           t = 4.17 s

d)

Duane's

d= 5 + 3(4.17)

d = 17.51 m

Alberts

d = 4.2(4.17)

d = 17.51 m

4 0
2 years ago
Read 2 more answers
A 150 g particle at x = 0 is moving at 8.00 m/s in the +x-direction. As it moves, it experiences a force given by Fx=(0.850N)sin
krok68 [10]

Answer:

9.98 m/s

Explanation:

The force acting on the particle is defined by the equation:

F=(0.850) sin (\frac{x}{2.00}) [N]

where x is the position in metres.

The acceleration can be found by using Newton's second law:

a=\frac{F}{m}

where

m = 150 g = 0.150 kg is the mass of the particle. Substituting into the equation,

a=\frac{0.850}{0.150}sin (\frac{x}{2.00})=5.67 sin(\frac{x}{2.00}) [m/s^2]

When x = 3.14 m, the acceleration is:

a=5.67 sin(\frac{3.14}{2.00})=5.67 m/s^2

Now we can find the final speed of the particle by using the suvat equation:

v^2-u^2=2ax

where

u = 8.00 m/s is the initial velocity

v is the final velocity

a=5.67 m/s^2

x = 3.14 m is the displacement

Solving for v,

v=\sqrt{u^2+2ax}=\sqrt{8.00^2+2(5.67)(3.14)}=9.98 m/s

And the speed is just the magnitude of the velocity, so 9.98 m/s.

4 0
2 years ago
As a person pushes a box across a floor, the energy from the person’s moving arm is transferred to the box, and the box and the
san4es73 [151]

Answer:

conserved

Explanation:

During this process the energy is conserved

3 0
2 years ago
Read 2 more answers
A sock with a mass of 0.03 kg is stuck to the inside of a clothes dryer spins
ValentinkaMS [17]

Answer:

15.71 m/s

Explanation:

We are given;

Time; t = 0.2 s

Radius; r = 0.5 m

The circumference will give us the distance covered.

Formula for circumference is 2πr

Thus; Distance = 2πr = 2 × π × 0.5 = π

Linear speed = distance/time = π/0.2 = 15.71 m/s

5 0
2 years ago
Scotesia swims from the north end to the south end of a 50.0 m pool in 20.0 s. As she begins to make the return trip , Sean, who
slega [8]

Answer:

a) 2.5m/s

b) 0.91m/s

c) 0m/s

Explanation:

Average velocity can be said to be the ratio of the displacement with respect to time.

Average speed on the other hand is the ratio of distance in relation to time

Thus, to get the average velocity for the first half of the swim

V(average) = displacement of first trip/time taken on the trip

V(average) = 50/20

V(average) = 2.5m/s

Average velocity for the second half of the swim will be calculated in like manner, thus,

V(average) = 50/55

V(average) = 0.91m/s

Average velocity for the round trip will then be

V(average) = 0/75, [50+25]

V(average) = 0m/s

3 0
2 years ago
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