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trapecia [35]
2 years ago
9

Geoff counts the number of oscillations of a simple pendulum at a location where the acceleration due to gravity is 9.80 m/s2, a

nd finds that it takes 25.0 s for 15 complete cycles. 1) calculate the length of the pendulum. (express your answer to three significant figures.
Physics
1 answer:
loris [4]2 years ago
7 0
Period of a simple pendulum = 2π √(L/G)

(25 sec/15) = 2π √(L / 9.8 m/s²)

5/3 sec  = 2π √(L/9.8 m/s²)

5 sec / 6π = √ (L/9.8 m/s²)

(5sec · √9.8m/s²) / 6π = √L

Square each side:

(25 s²) · (9.8 m/s²) / 36π²  =  L

L =  (25 · 9.8) / (36 π²) meters

L = 0.69 meter 
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Answer:

E = 55.9583\ Volts/meter

Explanation:

First let's find the electric potential using y = 22.5:

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