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trapecia [35]
2 years ago
9

Geoff counts the number of oscillations of a simple pendulum at a location where the acceleration due to gravity is 9.80 m/s2, a

nd finds that it takes 25.0 s for 15 complete cycles. 1) calculate the length of the pendulum. (express your answer to three significant figures.
Physics
1 answer:
loris [4]2 years ago
7 0
Period of a simple pendulum = 2π √(L/G)

(25 sec/15) = 2π √(L / 9.8 m/s²)

5/3 sec  = 2π √(L/9.8 m/s²)

5 sec / 6π = √ (L/9.8 m/s²)

(5sec · √9.8m/s²) / 6π = √L

Square each side:

(25 s²) · (9.8 m/s²) / 36π²  =  L

L =  (25 · 9.8) / (36 π²) meters

L = 0.69 meter 
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Integrated Concepts A basketball player jumps straight up for a ball. To do this, he lowers his body 0.300 m and then accelerate
____ [38]

Answer:

a) Velocity = 4.2m/s

b) Acceleration = 2.94m/s^2

c) Force exerted on the floor= 1401.4×10^3N

Explanation:

a) Velocity,V=sqrt(2×9.8×0.900)

V= 4.2m/s

b) Vf2= V^2+2ay2

a= 4.2^2 - 0/2×3

a= 17.64/6= 2.94m/s^2

c) Newton's 2nd law indicates:

Fnet= F - mg=ma

F= m(g+a)

F=110(9.8+2.94)

F=110×12.94

F= 1401.4N

4 0
2 years ago
Find the mass of a person walking west at a speed of 0.8 m/s with a momentum of 52.0 kg.m/s west.
KIM [24]

Answer:

mass of the person walking to west is 65 kg.

Given:

Momentum = 52 \frac{kg m}{s}

Speed = 0.8 \frac{m}{s}

To find:

Mass of the person = ?

Formula used:

Momentum is given by,

P = m × v

Where, P = momentum

m = mass

v = speed

Solution:

Momentum is given by,

P = m × v

Where, P = momentum

m = mass

v = speed

Mass = \frac{P}{v}

m = \frac{52}{0.8}

m = 65 kg

Thus, mass of the person walking to west is 65 kg.

5 0
2 years ago
Three particles are moving perpendicular to a uniform magnetic field and travel on circular paths (see the drawing). They have t
Vaselesa [24]

Explanation:

Radius of a charged particle is given by

r=mv / Bq

= k/ q

where   k   =   m v / B         is a constant.

i.e.   more is the magnitude of  charge, less is the radius. (inversely proportional)

From the diagram  r_3   >   r_2   >   r_1  (more the curvature, less is the radius)

( although drawing is not given i am assuming the above order, however, one can change the order as per the diagram. The concept used remains the same)

therefore,    q_1   >   q_2   >   q_3 .

7 0
2 years ago
A rock is rolling down a hill. At position 1, it’s velocity is 2.0 m/s. Twelve seconds later, as it passes position 2, it’s velo
mr Goodwill [35]

Answer

Hi,

correct answer is {D} 3.5 m/s²

Explanation

Acceleration is the rate of change of velocity with time. Acceleration can occur when a moving body is speeding up, slowing down or changing direction.

Acceleration is calculated by the equation =change in velocity/change in time

a= {velocity final-velocity initial}/(change in time)

a=v-u/Δt

The units for acceleration is meters per second square m/s²

In this example, initial velocity =2.0m/s⇒u

Final velocity=44.0m/s⇒v

Time taken for change in velocity=12 s⇒Δt

a= (44-2)/12  = 42/12

3.5 m/s²

Best Wishes!

5 0
2 years ago
The cockroach Periplaneta americana can detect a static electric field of magnitude 8.50 kN/C using their long antennae. If the
otez555 [7]

Answer:

0.647 nC

Explanation:

The force experienced by a charge due to the presence of an electric field is given by

F=qE

where

q is the charge

E is the magnitude of the electric field

In this problem, each antenna is modelled as it was a single point charge, experiencing a force of

F=5.50\mu N = 5.50\cdot 10^{-6} N

Therefore, if the electric field magnitude is

E=8.50 kN/C = 8500 N/C

Then the charge on each antenna would be

q=\frac{F}{E}=\frac{5.50\cdot 10^{-6} N}{8500 N/C}=6.47\cdot 10^{-10} C = 0.647 nC

8 0
2 years ago
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