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2 years ago

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Geoff counts the number of oscillations of a simple pendulum at a location where the acceleration due to gravity is 9.80 m/s2, a

nd finds that it takes 25.0 s for 15 complete cycles. 1) calculate the length of the pendulum. (express your answer to three significant figures.

1 answer:

loris [4]2 years ago

7 0

Period of a simple pendulum = 2π √(L/G)

(25 sec/15) = 2π √(L / 9.8 m/s²)

5/3 sec = 2π √(L/9.8 m/s²)

5 sec / 6π = √ (L/9.8 m/s²)

(5sec · √9.8m/s²) / 6π = √L

Square each side:

(25 s²) · (9.8 m/s²) / 36π² = L

L = (25 · 9.8) / (36 π²) meters

L = 0.69 meter

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