In this system we have the conservation of angular momentum: L₁ = L₂
We can write L = m·r²·ω
Therefore, we will have:
m₁ · r₁² · ω₁ = m₂ · r₂² · ω₂
The mass stays constant, therefore it cancels out, and we can solve for ω<span>₂:
</span>ω₂ = (r₁/ r₂)² · ω<span>₁
Since we know that r</span>₁ = 4r<span>₂, we get:
</span>ω₂ = (4)² · ω<span>₁
= 16 </span>· ω<span>₁
Hence, the protostar will be rotating 16 </span><span>times faster.</span>
<span>Storm cells in a squall line typically move from the southwest to the northeast, and as the mature cells in the northeast begin to die off, new ones are formed at the opposite end to advance the line. The air in the southwest corner has strong vertical updrafts that allow new cells to grow and develop into thunderstorms.</span>
Answer:
Angular displacement of the turbine is 234.62 radian
Explanation:
initial angular speed of the turbine is



similarly final angular speed is given as



angular acceleration of the turbine is given as

now we have to find the angular displacement is given as



Hi!
Mechanical advantage is defined as the<em> ratio of force produced by an object to the force that is applied to it.</em>
In our case, this would be the ratio of the force applied by the claw hammer on the nail to the force Joel applies to the claw hammer, which is
160:40 or 4:1
So the mechanical advantage of the hammer is four.
Hope this helps!
<span>The term "displacement" includes a change of position or change in an innate characteristic.
The first option would have someone travel in an L-shape, which definitely is a change in position from the starting point.
The second option of Ferris wheel with the same entrance and exit does not involve overall displacement since a person would return to the same place they began.
The third option of walking around the block does not involve overall displacement since, again, the person would return to the same place they began.
The fourth option of an escalator ride does involve overall displacement because a person would finish their journey in a different vertical location from where they started.
The last option does not involve overall displacement because one lap around a track will return you to the same place you began.</span>