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Sidana [21]
2 years ago
5

The newly formed xenon nucleus is left in an excited state. Thus, when it decays to a state of lower energy a gamma ray is emitt

ed. If the wavelength of the emitted gamma ray is 3.44×10−12 m , what is the decrease in mass, ΔmXe, of the xenon nucleus as a result of this decay?
Physics
1 answer:
nevsk [136]2 years ago
6 0

Answer:3.87*10^-4

Explanation:

What is the decrease in mass, delta mass Xe , of the xenon nucleus as a result of this deca

We have been given the wavelength of the gamma ray, find the frequency using c = freq*wavelength.

C=f*lambda

3*10^8=f*3.44*10^-12

F=0.87*10^20 hz

Then with the frequency, find the energy emitted using equation

E=hf E = freq*Plank's constant

E=.87*10^20*6.62*10^-34

E=575.94*10^(-16)

With this energy, convert into MeV from joules.

With the energy in MeV, use E=mc^2 using c^2 = 931.5 MeV/u.

Plugging and computing all necessary numbers gives you

3.87*10^-4 u.

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B. running one mile faster than normal

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Explanation:

  • A substance will floats if it is having lower density than the density of the liquid in which it is placed.
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1) Density of gasoline = 0.748 g/cm^3

Density of the gasoline is less than the the density of corn syrup which means it will float in corn syrup.

2) Density of water = 1 g/cm^3

Density of the water is less than the the density of corn syrup which means it will float in corn syrup.

3) Density of honey = 1.45 g/cm^3

Density of the gasoline is more than the the density of corn syrup which means it will sink in corn syrup.

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Density of the titanium is more than the the density of corn syrup which means it will sink in corn syrup.

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2 years ago
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A ship maneuvers to within 2.50 x 103 m of anisland's 1.80 x 103 m high mountain peak and fires aprojectile at an enemy ship 6.1
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Answer:

Distance between peak height (vertically) of projectile and mountain height = (2975.2 - 1800) = 1175.2 m

Distance between where the projectile lands and ship B = (3188.8 - 3110) = 8.8 m

Explanation:

Given the velocity and angle of shot of the projectile, one can calculate the range and maximum height attained by the projectile.

H = (v₀² Sin²θ)/2g

v₀ = initial velocity of projectile = 2.50 × 10² m/s = 250 m/s

θ = 75°, g = 9.8 m/s²

H = 250² (Sin² 75)/(2 × 9.8) = 2975.2 m

Range of projectile

R = v₀² (sin2θ)/g

R = 250² (sin2×75)/9.8

R = 250² (sin 150)/9.8 = 3188.8 m

Height of mountain = 1.80 × 10³ = 1800 m

Maximum height of projectile = 2975.2 m

Distance between peak height (vertically) of projectile and mountain height = 2975.2 - 1800 = 1175.2 m

Distance of ship B from ship A = 2.5 × 10³ + 6.1 × 10² = 2500 + 610 = 3110 m

Range of projectile = 3188.8 m

Distance between where the projectile lands and ship B = 3188.8 - 3110 = 8.8 m

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Answer:

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            T-W₁ = m a

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c) in the center of mass all external forces are applied, they relate it is

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