Answer:
Explanation:
The magnetic field due to straight wire is into the square coil.
As the current in straight wire decreases the magnetic flux in the coil decreases
. The induced magnetic field is into the coil.The induced current is along +y direction
The collision is a form of inelastic collision because the
it forms a single mass after is collides. So it can be solve by momentum
balance
( 0.08 kg * 50 m/s ) + ( 0.06 kg * 50 m/s) = ( 0.08 + 0.06
kg ) v
V = 50 m/s
So the kinetic energy lost is
KE = 0.5 (50 m/s)^2) *( 0.14 – 0.08kg )
KE = 75 J
Answer:
the length of the now stationary spacecraft = 89.65m
Explanation:
In contraction equation, Length contraction L is the shortening of the measured length of an object moving relative to the observer’s frame.
Thus, it has a formula;
L = L_o(√(1 - (v²/c²))
Where in this question;
L = 71m and v = 0.610 c
Thus;
71 = L_o (√(1 - ((0.61c)²/c²))
c² will cancel out to give;
71 = L_o (√(1 - 0.61²)
71 = L_o (√(1 - 0.61²)
71 = 0.792L_o
L_o = 71/0.792
L_o = 89.65m
Answer:
You won't feel any change and will have no way to know that you've left the earth.
Explanation:
One of the formulations of the principle says that the properties of an inertial system under the effect of a gravitational field are the same as a non-inertial(accelerated) system. The inertial system under the effect of a gravitational field occurs when you are in the room on earth, and when the room is sent accelerating through space you have the non-inertial system. Both have the same properties, so it's impossible to tell the difference if you can't look outside.
Answer:
W= -2.5 (p₁*0.0012) joules
Explanation:
Given that p₀= initial pressure, p₁=final pressure, Vi= initial volume=0 and Vf=final volume= 6/5 liters where p₁=p₀ then
In adiabatic compression, work done by mixture during compression is
W= 
where f= final volume and i =initial volume, p=pressure
p can be written as p=K/V^γ where K=p₀Vi^γ =p₁Vf^γ
W= 
W= K/1-γ ( 1/Vf^γ-1 - 1/Vi^γ-1)
W=1/1-γ (p₁Vf-p₀Vi)
W= 1/1-1.40 (p₁*6/5 -p₀*0)
W= -2.5 (p₁*6/5*0.001) changing liters to m³
W= -2.5 (p₁*0.0012) joules
