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Oduvanchick [21]
2 years ago
5

A truck traveling down the highway collides with a slower moving mosquito traveling in the same direction. Which of the followin

g statements is true during the collision? A. the truck exerts a larger force on the mosquito exerts on the truck. B. The truck and mosquito exert the same size force on each other. C. The mosquito exerts a larger force on the truck than the truck exerts on the mosquito. What law of physics did you use in determining your answer?
Physics
1 answer:
Ipatiy [6.2K]2 years ago
6 0

Answer:

B. The truck and mosquito exert the same size force on each other.

Explanation:

Newton's third law (law of action-reaction) states that

"When an object A exerts a force (action) on an object B, then object B exerts an equal and opposite force (reaction) on object A"

In this case, we can call

object A = the truck

object B = the mosquito

Thereforce according to Newton's third law, the force exerted by the truck on the mosquito is equal in magnitude to the force exerted by the mosquito on the truck (and in opposite direction).

The reason for which the mosquito will experience much more damage is the fact that the mosquito's mass is much smaller than the truck's mass, and since the acceleration is inversely proportional to the mass:

a=\frac{F}{m}

the mosquito will experience a much larger deceleration than the truck, therefore much more damage.

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Astronauts in the International Space Station must work out every day to counteract the effects of weightlessness. Researchers h
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Answer:

  33.725 rpm

Explanation:

The relationship between rotational speed in radians per second and acceleration is ...

  \omega=\sqrt{\dfrac{a}{r}}

We want the rotation rate in RPM, so we need the conversion ...

  \text{RPM}=\dfrac{\text{rad}}{\text{s}}\cdot\dfrac{1\,\text{rev}}{2\pi\,\text{rad}}\cdot\dfrac{60\,\text{s}}{1\,\text{min}}

Then the required rotational speed in RPM is ...

  RPM=\sqrt{\dfrac{a}{r}}\cdot\dfrac{30}{\pi}=\dfrac{30}{\pi}\sqrt{\dfrac{1.4\cdot 9.8}{1.1}}\approx 33.725

The rotation rate needs to be about 33.7 rpm to give an acceleration of 1.4g at the astronaut's feet.

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2 years ago
During summer break, Jamie's family went camping in the mountains. There were no roads to their camp, 8 miles away, and it took
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The Answer is B

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The surface pressures at the bases of warm and cold columns of air are equal. air pressure in the warm column of air will ______
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In atmospheric science, surface pressure<span> is the atmospheric </span>pressure<span> at a location on Earth's </span>surface<span>. It is directly proportional to the mass of air over that location. For numerical reasons, atmospheric models such as general circulation models (GCMs) usually predict the nondimensional logarithm of </span>surface pressure<span>.

The answer is decrease more slowly


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2 years ago
What would the speed of each particle be if it had the same wavelength as a photon of yellow light (????=575.0 nm)? Proton (mass
PilotLPTM [1.2K]

Answer:

Proton: v=0.689 m/s

Neutron: v=0.688 m/s

Electron: v=1265.078 m/s

Alpha particle: v=0.173 m/s

Explanation:

De Broglie equation allows you to calculate the “wavelength” of an electron or any other particle or object of mass m that moves with velocity v:

λ=\frac{h}{mv}

h is the Planck constant: 6.626×10⁻³⁴\frac{kg.m^2}{s}

We know that the wavelength of the particle is 575 nm (575×10⁻⁹m), so we find the velocity v for each particle:

λ=\frac{h}{mv}

v=h÷(mλ)

<u>Proton:</u>

m=1.673×10⁻²⁴ g · \frac{1kg}{1000g}=1.673×10⁻²⁷ kg

v=h÷(mλ)

v=6.626×10⁻³⁴\frac{kg.m^2}{s}÷(1.673×10⁻²⁷ kg×575×10⁻⁹m)

v=0.689 m/s

<u>Neutron:</u>

m=1.675×10⁻²⁴ g · \frac{1kg}{1000g}=1.675×10⁻²⁷ kg

v=h÷(mλ)

v=6.626×10⁻³⁴\frac{kg.m^2}{s}÷(1.675×10⁻²⁷ kg×575×10⁻⁹m)

v=0.688 m/s

<u>Electron:</u>

m= 9.109×10⁻²⁸ g · \frac{1kg}{1000g}=9.109×10⁻³¹ kg

v=h÷(mλ)

v=6.626×10⁻³⁴\frac{kg.m^2}{s}÷(9.109×10⁻³¹ kg×575×10⁻⁹m)

v=1265.078 m/s

<u>Alpha particle:</u>

m=6.645×10⁻²⁴ g · \frac{1kg}{1000g}=6.645×10⁻²⁷ kg

v=h÷(mλ)

v=6.626×10⁻³⁴\frac{kg.m^2}{s}÷(6.645×10⁻²⁷ kg×575×10⁻⁹m)

v=0.173 m/s

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