answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Jlenok [28]
2 years ago
13

Suppose an X-ray binary is found in which the visible star is a 12 M⦿ red giant, the orbital period is 3.65 days, and the semima

jor axis is 0.12 AU. Show whether the companion likely to be a neutron star or a black hole.
Physics
1 answer:
nataly862011 [7]2 years ago
8 0

Answer:

If the mass of a star is greater than 3 solar masses, it will create a black hole. If its mass is less, it will create a neutron star.

Explanation:

If a star's gravity is high enough, when it condenses on itself, it will form a black hole. Otherwise, it will create a large amount of highly dense matter, such as a neutron star. It can be said that if the mass of a star is greater than 3 solar masses, it will create a black hole. If its mass is less, it will create a neutron star.

You might be interested in
In Paul Hewitt's book, he poses this question: "If the forces that act on a bullet and the recoiling gun from which it is fired
Sauron [17]
They have different accelerations because of their masses. According to Newton's Second Law, an objects acceleration is inversely proportional to its mass. Therefore the object with the larger mass, in this case the gun, will have a smaller acceleration. In the same way, the less massive object, being the bullet, will have a higher acceleration.

Hope this helps :)
4 0
2 years ago
A 1-kg mass is dropped from a third floor window. The acceleration of the mass is found to be 8 m/s2. What is the average force
Paha777 [63]
Summary:
m=1kg
a=8 m/s^2
g= 9,8 m/s^2
F(ar)=?


I hope to help you

7 0
2 years ago
A section of highway has the following flowdensity relationship q = 50k − 0.156k2 [with q in veh/h and k in veh/mi]. What is the
lions [1.4K]

Answer:

a) capacity of the highway section = 4006.4 veh/h

b) The speed at capacity = 25 mph

c) The density when the highway is at one-quarter of its capacity = k = 21.5 veh/mi or 299 veh/mi

Explanation:

q = 50k - 0.156k²

with q in veh/h and k in veh/mi

a) capacity of the highway section

To obtain the capacity of the highway section, we first find the k thay corresponds to the maximum q.

q = 50k - 0.156k²

At maximum flow density, (dq/dk) = 0

(dq/dt) = 50 - 0.312k = 0

k = (50/0.312) = 160.3 ≈ 160 veh/mi

q = 50k - 0.156k²

q = 50(160.3) - 0.156(160.3)²

q = 4006.4 veh/h

b) The speed at the capacity

U = (q/k) = (4006.4/160.3) = 25 mph

c) the density when the highway is at one-quarter of its capacity?

Capacity = 4006.4

One-quarter of the capacity = 1001.6 veh/h

1001.6 = 50k - 0.156k²

0.156k² - 50k + 1001.6 = 0

Solving the quadratic equation

k = 21.5 veh/mi or 299 veh/mi

Hope this Helps!!!

3 0
2 years ago
A packing crate with mass 80.0 kg is at rest on a horizontal, frictionless surface. At t = 0 a net horizontal force in the +x-di
Nataly [62]

Answer:

Final speed of the crate is 15 m/s

Explanation:

As we know that constant force F = 80 N is applied on the object for t = 12 s

Now we can use definition of force to find the speed after t = 12 s

F . t = m(v_f - v_i)

so here we know that object is at rest initially so we have

80 (12) = 80( v_f - 0)

v_f = 12 m/s

Now for next 6 s the force decreases to ZERO linearly

so we can write the force equation as

F = 80 - \frac{40}{3} t

now again by same equation we have

\int F .dt = m(v_f - v_i)

\int (80 - (40/3)t) dt = 80(v_f - 12)

80 t - \frac{40t^2}{6} = 80(v_f - 12)

put t = 6 s

480 - 240 = 80(v_f - 12)

v_f = 12 + 3

v_f = 15 m/s

6 0
2 years ago
One of the Lady Spartans was falling to the ground after
dem82 [27]

Answer:

Explanation:

Given that,

A lady falling has a final velocity of 4m/s

v = 4m/s

Mass of the lady is 60kg.

m = 60kg

Using conservation of energy, the potential energy of the body from the point where the lady is dropping is converted to the final kinetic energy of the lady.

Therefore,

P.E = K.E(final) = ½mv²

P.E = ½ × 60 × 4²

P.E = 480 J.

0 0
2 years ago
Other questions:
  • Anne releases a stone from a height of 2 meters. She measures the kinetic energy of the stone at 9.8 joules at the exact point i
    14·2 answers
  • Waves inwhich the particles vibrate at right angles to direction is called
    8·1 answer
  • The intensity at a distance of 6.0 m from a source that is radiating equally in all directions is 6.0 × 10-10 w/m2 . what is the
    5·1 answer
  • Which correctly identifies the parts of a transverse wave? A: crest B: amplitude C: wavelength D: trough A: trough B: amplitude
    10·2 answers
  • Which of the following graphs shows the relationship between two variables that obey the inverse square law?​
    12·1 answer
  • A balloon drifts 140m toward the west in 45s ; then the wind suddenly changes and the balloon flies 90m toward the east in the n
    10·1 answer
  • In the swing carousel amusement park ride, riders sit in chairs that are attached by a chain to a large rotating drum as shown i
    7·1 answer
  • To penetrate armor, a projectile's point concentrates force in a small area, creating a stress large enough that the armor fails
    5·1 answer
  • 3. A very light bamboo fishing rod 3.0 m long is secured to a boat at the bottom end. It is
    13·1 answer
  • The index of refraction of water is 1.33. If you (or a fish) were under calm water swimming in the daytime, looking upward you w
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!