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GaryK [48]
2 years ago
5

Consider a sign suspended on a boom that is supported by a cable, as shown. What is the proper equation to use for finding the n

et force in the y direction?
Fnety = (FT)(sin 32°) + Fg
Fnety = (FT)(sin 32°) – Fg
Fnety = (FT)(cos 32°) + Fg
Fnety = (FT)(cos 32°) – Fg
Physics
2 answers:
-Dominant- [34]2 years ago
8 0

Answer:

B: Fnety = (FT)(sin 32°) – Fg

Explanation:

oksian1 [2.3K]2 years ago
3 0
Fnety = (FT)(sin 32°) – Fg Or the answer B, I checked it.
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Which number can each term of the equation be multiplied by to eliminate the fractions before solving? 6 – x + = 6 minus StartFr
zysi [14]

Answer:

We need to multiply 12 to each term to eliminate fractions.

Explanation:

Given expression:

6-\frac{3}{4}x+\frac{1}{3}=\frac{1}{2}x+5

To eliminate the fraction we need to multiply each term by least common multiple of the denominators of the fraction.

The denominators in the above expressions are:

4, 3 and 2

The multiples of each can be listed below.

2⇒ 2,4,6,8,10,<u>12</u>,14,16.....

3⇒ 3,6,9,<u>12</u>,15,18

4⇒ 4,8,<u>12</u>.......

From the list of the multiples stated, we can see the least common multiple is 12.

So we will multiply each term by 12.

Multiplying 12 to both sides.

12(6-\frac{3}{4}x+\frac{1}{3})=12(\frac{1}{2}x+5)

Using distribution,

72-9x+4=6x+60

Thus we successfully eliminated the fractions.

5 0
2 years ago
Read 2 more answers
Slick Willy is in traffic court (again) contesting a $50.00 ticket for running a red light. "You see, your Honor, as I was appro
Masteriza [31]

Answer:

61578948 m/s

Explanation:

λ_{actual} = λ_{observed} \frac{c+v_{o}}{c}

687 = 570 (\frac{3 * 10^{8} +v_{o} }{3 * 10^{8}} )

v_{o} = 61578948 m/s

So Slick Willy was travelling at a speed of 61578948 m/s to observe this.

8 0
2 years ago
Read 2 more answers
A toy car is given an initial velocity of 5.0 m/s and experiences a constant acceleration of 2.0 m/s656-03-02-00-00_files/i02900
Whitepunk [10]
It would be 17 m/s

If we use

V2 = V1 + a*t
Sub in 5 for v1
2m/s*2 for a
And
6 for t
That should give you the answer.
5 0
2 years ago
Read 2 more answers
2. Harry is pushing a car down a level road at 2.0 m/s with a force of 243 N. The total force
Arte-miy333 [17]

b) Equal to 243 N.

Explanation:

The total force acting on the car in the opposite direction including the road friction and air resistance is equal to 243 N.

This is in conformity with newton's third law of motion.

Newton's third law of motion states that "action and reaction are equal and opposite in direction. "

  • The action force is that of the pull by Harry acting on the car.
  • The reaction force is in the opposite direction.
  • Both action and reaction force equal and opposite and magnitude and direction

learn more:

Newton's laws brainly.com/question/11411375

#learnwithBrainly

3 0
2 years ago
B. A hydraulic jack has a ram of 20 cm diameter and a plunger of 3 cm diameter. It is used for lifting a weight of 3 tons. Find
lozanna [386]

Answer:

option (b)

Explanation:

According to the Pascal's law

F / A = f / a

Where, F is the force on ram, A be the area of ram, f be the force on plunger and a be the area of plunger.

Diameter of ram, D = 20 cm, R = 20 / 2 = 10 cm

A = π R^2 = π x 100 cm^2

F = 3 tons = 3000 kgf

diameter of plunger, d = 3 cm, r = 1.5 cm

a = π x 2.25 cm^2

Use Pascal's law

3000 / π x 100 = f / π x 2.25

f = 67.5 Kgf

4 0
2 years ago
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