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NNADVOKAT [17]
2 years ago
6

Tara is giving a speech on the how to get a U.S. passport for the first time. During her speech, she tells the audience the requ

irements for making an application and then the steps that must be followed. In her conclusion, she begins by saying, "In conclusion, when you apply for a passport, you will need proof of citizenship, a photo ID, a filled-out application form, and a photo that meets specific requirements. When you present these items at an acceptance facility, you will also need to pay a fee." How is Tara meeting the major objectives of a conclusionAn individual suffering from a high cholesterol level in her blood has 248 mg of cholesterol per 100 mL of blood. If the total blood volume of the individual is 5.3 L, how many grams of total blood cholesterol does the individual's body contain?
Physics
1 answer:
Alchen [17]2 years ago
7 0

Answer:

a. 1. she informed the audience when she was concluding

2. She simply outlined the steps tying her conclusion to the topic

3. her conclusion was concise and simple.

b. 13.1 grams

Explanation:

a. signalling the end of a speech prepares the mind of the audience and leaves them satisfied, and Kara correctly signaled the end of her speech when she said "In conclusion".

Also, Kara summarized the ideas in her speech by simply outlining the requirements needed to get a U.S passport.

Her conclusion was concise and simple which is very important especially for lengthy speeches because the audience at this point must be getting tired and distracted.

b. Amount of cholesterol in 100 mL of blood = 248 mg

Total Volume of blood = 5.3 Liters.

the question is asking us to find the total grams of cholesterol in the individual's body, that is the total grams of cholesterol in 5.3 Liters of the individuals blood.

To solve, let us use the following steps:

1. unify the units of measuring volume.

since the first volume is given in Milliliters, I will convert the second volume (5.3 Liters) to milliliters too. To do this, note that:

1 liter = 1000 Milliliter (mL)

∴ 5.3 Liters = 5.3 × 1000 = 5300 Milliliters (mL)

2. Calculate the amount of cholesterol in 5300 mL.

100 mL = 248 mg of cholesterol

∴ 1 mL = \frac{248}{100\\} = 2.48 mg

∴ 5300 mL = 2.48 × 5300 = 13,144 mg of cholesterol.

3. Convert the amount of cholesterol from Milligram to gram

Since the question asked for the gram of cholesterol, not the milligram of cholesterol, converting from milligram to gram, we use the following steps:

1000 mg = 1 g

∴ 1 mg = \frac{1}{1000} g

∴ 13144 mg = 13144 × \frac{1}{1000} = \frac{13144}{1000} = 13.144 ≅ 13.1 g of cholesterol ( 1 decimal place).

I suggest you go and study the conversion relationships between the sub units milli, micro, centi and deci.

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Answer:

2 x 10⁻³ volts

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\frac{dA}{dt} = rate of change of area of the loop = 20 cm²/s = 20 x 10⁻⁴ m²

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We know that speed is given by dividing distance by time or multiplying length and frequency. The speed of the father will be given by Lf where L is the length of the father’s leg ad f is the frequency.

We know that frequency of simple pendulum follows that f=\frac {1}{2\pi} \sqrt {\frac {g}{l}}

Now, the speed of the father will be V=Lf= L\times (\frac {1}{2\pi} \sqrt {\frac {g}{l}}) while for the child the speed will be v=\frac {L}{2}\times (\frac {1}{2\pi} \sqrt {\frac {g}{0.5l}})

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\frac {V}{v}=\frac {\frac {L}{2}\times (\frac {1}{2\pi} \sqrt {\frac {g}{0.5l}})}{ L\times (\frac {1}{2\pi} \sqrt {\frac {g}{l}})}\\\frac {V}{v}=\frac {\sqrt {2}}{2}\\\boxed{v=\frac {V}{\sqrt {2}}}

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Kara Less was applying her makeup when she drove into South's busy parking lot last Friday morning. Unaware that Lisa Ford was s
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Answer

given,

Mass of Kara's car = 1300 Kg

moving with speed = 11 m/s

time taken to stop = 0.14 s

final velocity = 0 m/s

distance between Lisa ford and Kara's car = 30 m

a) change in momentum of Kara's car

  Δ P = m Δ v                  

  \Delta P = m (v_f-v_i)

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    I = - 1.43 x 10⁴ kg.m/s

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  I = F x t

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use the conservation of angular momentum as no external torque is applied on the system.

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0.5 x MR² x ωo = 0.6 MR² x ω'

ω' = 0.83 ω

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