The question is asking to choose among the following choices that could complete the question about the inertia, base on my research and further investigation, the possible answer would be letter B. Gravity. I hope you are satisfied with my answer and feel free to ask for more
Answer:
Approximately 
.
Explanation:
The formula for the kinetic energy 
of an object is:
,
where
is the mass of that object, and
is the speed of that object.
Important: Joule (
) is the standard unit for energy. The formula for requires two inputs: mass and speed. The standard unit of mass is 
while the standard unit for speed is 
. If both inputs are in standard units, then the output (kinetic energy) will also be in the standard unit (that is: joules,
Convert the unit of the arrow's mass to standard unit:
.
Initial of this arrow:
.
That's the same as the energy output of this bow. Hence, the efficiency of energy transfer will be:
.
Answer:
the length of the now stationary spacecraft = 89.65m
Explanation:
In contraction equation, Length contraction L is the shortening of the measured length of an object moving relative to the observer’s frame.
Thus, it has a formula;
L = L_o(√(1 - (v²/c²))
Where in this question;
L = 71m and v = 0.610 c
Thus;
71 = L_o (√(1 - ((0.61c)²/c²))
c² will cancel out to give;
71 = L_o (√(1 - 0.61²)
71 = L_o (√(1 - 0.61²)
71 = 0.792L_o
L_o = 71/0.792
L_o = 89.65m
Answer:
K_b = 78 J
Explanation:
For this exercise we can use the conservation of energy relations
starting point. Lowest of the trajectory
Em₀ = K = ½ mv²
final point. When it is at tea = 50º
Em_f = K + U
Em_f = ½ m v_b² + m g h
where h is the height from the lowest point
h = L - L cos 50
Em_f = ½ m v_b² + mg L (1 - cos50)
energy be conserve
Em₀ = Em_f
½ mv² = ½ m v_b² + mg L (1 - cos50)
K_b = ½ m v_b² + mg L (1 - cos50)
let's calculate
K_b = ½ 2.0 6.0² + 2.0 9.8 6.0 (1 - cos50)
K_b = 36 +42.0
K_b = 78 J
The indicated data are of clear understanding for the development of Airy's theory. In optics this phenomenon is described as an optical phenomenon in which The Light, due to its undulatory nature, tends to diffract when it passes through a circular opening.
The formula used for the radius of the Airy disk is given by,
Where,
Range of the radius
wavelength
f= focal length
Our values are given by,
State 1:
State 2:
Replacing in the first equation we have:
And also for,
Therefor, the airy disk radius ranges from 
to 
