Answer:
Instantaneous speed of contact point will be ZERO
Explanation:
As we know that disc is rolling without slipping on horizontal surface
So here the speed of center of the disc is given as
v = 5 m/s
now at the contact point the tangential speed will be in reverse direction
now we know that net contact speed with respect to its lower surface must be zero
so net velocity of contact point with respect to its lower surface must be ZERO here
Answer:
a=
Explanation:
The net force, of the box is expressed as a product of acceleration and mass hence
where m is mass and a is acceleration
Making a the subject, a=
From the attached sketch,
∑ where
is frictional force and
is horizontal angle
Substituting ∑ as
in the equation where we made a the subject
a=
Since we’re given the value of F as 240N, as 41.5N,
as
and mass m as 30kg
a=
Answer:
shown in the attachment
Explanation:
The detailed step by step and necessary mathematical application is as shown in the attachment.
Answer:
the tension in the rope between the boxes is equal to 88 N
Explanation:
given,
the force applied on one body F = 176 N
When two bodies are moving on horizontal plane at constant velocity then their kinetic friction (f k) is equal to applied force F
According to newton third law the resultant force acting on one body is equal to the resultant force acting on the another body.
T is the tension in the rope
T - F = - (T - F)
T - 176 = - (T - 0)
2 T = 176
T = 176/2 = 88 N
so, the tension in the rope between the boxes is equal to 88 N
Answer:
Explanation:
Given data
velocity v₀=20 cm/s at time t=3s
velocity vf=0 at time t=8 s
To find
Average Acceleration at time=3s to 8s
Solution
As we know that acceleration is first derivative of velocity with respect to time