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2 years ago

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Add the following numbers, using scientific notation and the correct amount of significant digits. 3.4⋅10 8m + 4.56⋅10 9m = ____

_.
A 4.9 ⋅10 9m
B 4.9 ⋅10 8m
C 7.96 ⋅10 9m
D 7.96 ⋅10 8m

2 answers:

Gnoma [55]2 years ago

7 0

The answer is B
<span>B 4.9 ⋅10 8m
</span>

Artist 52 [7]2 years ago

5 0

Answer:

The answer is A) 4.9 × 10^9

Explanation:

I literally just did the calculation, the other dude is wrong.

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While traveling from Boston to Hartford, Person A drives at a constant speed of 55 mph for the entire trip. Person B drives at 6

Ne4ueva [31]

Answer:

B will take 1.034 times the time of A from Boston to Hartford.

Explanation:

Let the distance from Boston to Hartford be S.

Person A drives at a constant speed of 55 mph for the entire trip,

Time taken by person A

$t_A=\frac{S}{55}$

Person B drives at 65 mph for half the distance and then drives 45 mph for the second half of the distance.

Time taken by person B

$t_B=\frac{\frac{S}{2}}{65}+\frac{\frac{S}{2}}{45}=\frac{S}{130}+\frac{S}{90}=\frac{220S}{130\times 90}=\frac{11S}{585}$

Ratio of time of arrival of B to A

$\frac{t_B}{t_A}=\frac{\frac{11S}{585}}{\frac{S}{55}}=\frac{121}{117}=1.034$

B will take 1.034 times the time of A from Boston to Hartford.

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2 years ago

An experiment to measure the speed of light uses an apparatus similar to Fizeau's. The distance between the light source and the

Marina86 [1]

Answer:

$2.88*10^{8} m/s$

Explanation:

The speed of light is given by

$c=\frac {2d}{t}$ and $t=\frac {\theta}{\omega}$ hence

$c=\omega\frac {2d}{\theta}$

Speed of light is given by

$c=900\times 2\pi(\frac {2\times 10}{\frac {2\pi}{2*800}}})=2.88*10^{8} m/s$

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2 years ago

You throw a tennis ball (mass 0.0570 kg) vertically upward. It leaves your hand moving at 15.0 m/s. Air resistance cannot be neg

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Answer:195 J

Explanation:

Given

mass of ball $m=0.0570\ kg$

ball leaves the hand with $u=15\ m/s$

maximum height reached by ball $h=8\ m$

Initial Mechanical energy when ball just leaves the hand

$M.E._1=(P.E.+K.E.)_1$

$M.E._1=(mgh)_1+(\frac{1}{2}mv^2)_1$

considering hand to be datum so h_1=0[/tex]

so Potential energy at ground is zero

$M.E._1=\frac{1}{2}\times m\times (15)^2$

$M.E._1=6.41\ J$

Mechanical Energy at highest point

$(M.E.)_2=(P.E.+K.E.)_2$

at highest Point velocity is zero

$(M.E.)_2=mgh_2+0$

$(M.E.)_2=0.0570\times 9.8\times 8$

$(M.E.)_2=4.46\ J$

Decrease in Mechanical energy

$(M.E.)_1-(M.E.)_2=6.41-4.46$

$(M.E.)_1-(M.E.)_2=1.95\ J$

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2 years ago

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Answer: 10

Explanation subtract

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2 years ago

A policeman kicks in a door with a force of 4500 N. What force does the door apply to the policeman’s leg?

Soloha48 [4]

Answer:

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Source: Brainly

The police officer must be angry 0_0

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2 years ago