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s344n2d4d5 [400]

1 year ago

6

A rock climber’s shoe loosens a rock, and her climbing buddy at the bottom of the cliff notices that the rock takes 3.20 s to fa

ll to the ground. How high up the cliff is the rock climber?

1 answer:

Debora [2.8K]1 year ago

8 0

Answer:

50.176 [m].

Explanation:

1) the required height can be calculated using the formula:

h=V₀*t+1/2* g*t₂, where V₀ - initial velocity of the rock, t - elapsed time, g - 9.8 m/s²;

2) if V₀=0, t=3.2, g=9.8, then

h=0.5*9.8*3.2²=1024*49*10⁻³=50.176 [m].≈50[m].

You might be interested in

A toroidal solenoid has an inner radius of 12.0 cm and an outer radius of 15.0 cm . It carries a current of 1.50 A . Part A How

tensa zangetsu [6.8K]

Answer:

The number of turns is $N = 1750 \ turns$

Explanation:

From the question we are told that

The inner radius is $r_i = 12.0 \ cm = 0.12 \ m$

The outer radius is $r_o = 15.0 \ cm = 0.15 \ m$

The current it carries is $I = 1.50 \ A$

The magnetic field is $B = 3.75 mT = 3.75 *10^{-3} \ T$

The distance from the center is $d = 14.0 \ cm = 0.14 \ m$

Generally the number of turns is mathematically represented as

$N = \frac{2 * \pi * d * B}{ \mu_o * r_o }$

Generally $\mu_o$ is the permeability of free space with value

$\mu_o = 4\pi * 10^{-7} \ N/A^2$

So

$N = \frac{2 * 3.142 * 0.14 * 3.75 *10^{-3} }{ 4\pi * 10^{-7} * 0.15 }$

$N = 1750 \ turns$

5 0

1 year ago

The total charge that an automobile battery can supply without being recharged is given in terms of ampere-hours. A typical 12 V

Lelechka [254]

Answer:

7.894 Hours.

Explanation:

Based on information number hours that this battery will last with give load has mathematical relation of.

$t = \frac{60Ah}{load in amperes.}$

with load 60A t = 1h, 30A t = 2h so on and forth.

two head lights draw total current of 2x3.8A = 7.6A.

putting this in above relation gives.

$t = \frac{60Ah}{7.6A}=7.894 h$ .

That is how long will it be before battery is dead.

6 0

1 year ago

The gravitational force of a star on an orbiting planet 1 is f1. planet 2, which is three times as massive as planet 1 and orbit

Margaret [11]

Let us consider two bodies having masses m and m' respectively.

Let they are separated by a distance of r from each other.

As per the Newtons law of gravitation ,the gravitational force between two bodies is given as - $F = G\frac{mm'}{r^{2} }$ where G is the gravitational force constant.

From the above we see that F ∝ mm' and $F\alpha \frac{1}{r^{2} }$

Let the orbital radius of planet A is $r_{1}$ = r and mass of planet is $m_{1}$ .

Let the mass of central star is m .

Hence the gravitational force for planet A is $f_{1} =G \frac{m_{1}*m }{r^{2} }$

For planet B the orbital radius $r_{2} =2r_{1}$ and mass $m_{2} = 3 m_{1}$

Hence the gravitational force $f_{2} =G\frac{m m_{2} }{r^{2} }$

$f_{2} =G\frac{m*3m_{1} }{[2r_{1}] ^{2} }$

$= \frac{3}{4} G\frac{mm_{1} }{r_{1} ^{2} }$

Hence the ratio is $\frac{f_{2} }{f_{1} } = \frac{\frac{3}{4}G mm_{1/r_{1} ^2} }{Gmm_{1}/r_{1} ^2 }$

$=\frac{3}{4}$ [ ans]

3 0

2 years ago

Read 2 more answers

The best way to cool soft and thick foods (such as beans, sauce or chili) when using the refrigerator is?

AnnZ [28]

<span>The best way to cool soft and thick foods when using the refrigerator is by having them to be placed and poured on a pan or another way is by having them to be placed in one container in which they are in a water bath, to be heated of.</span>

3 0

1 year ago

Read 2 more answers

A bowling ball starts from rest and moves 300 m down a long, downwardly angled track in 22.4 sec.a. What is its speed at the end

Sergio [31]

Answer:

The speed at the end of the track = 27 m/s

The acceleration = 1.2 m/s²

Please find the Δx vs Δt, v vs Δt, a vs Δt

Explanation:

We have;

x = u·t + 1/2·a·t²

Where;

x = The distance = 300 m

u = The initial velocity = 0 m/s (Ball at rest)

t = The time taken = 22.4 s

Therefore;

300 = 0 + 1/2×a×22.4²

a = 2×300/22.4² = 1.19579 ≈ 1.2 m/s²

v = u + a×t

∴ v = 0 + 1.2 × 22.4 = 26.88 ≈ 27 m/s

Part of the table of values is as follows;

t, x, v

0, 0, 0

0.4, 0.095663, 0.478316

0.8, 0.382653, 0.956632

1.2, 0.860969, 1.434948

1.6, 1.530611, 1.913264

2, 2.39158, 2.39158

2.4, 3.443875, 2.869896

2.8, 4.687497, 3.348212

3.2, 6.122445, 3.826528

3.6, 7.748719, 4.304844

4 0

1 year ago