Answer:
C - higher volume
Explanation:
The pitch or frequency of sound that an object can produce depends upon its size and configuration . The shape of hand of all are same so the frequency of sound produced by hands of all will be almost same . Hence frequency of sound produced by the hands of Anand and Kumar would have been almost the same .
But the intensity of sound produced by them would have been different . Intensity represents energy a sound carries . Hard hitting clap will produce sound of higher intensity . Intensity of sound is also called high volume sound . So Kumar's clap will carry greater energy and hence greater volume of sound .
Answer:
The total charge on the rod is 47.8 nC.
Explanation:
Given that,
Charge = 5.0 nC
Length of glass rod= 10 cm
Force = 840 μN
Distance = 4.0 cm
The electric field intensity due to a uniformly charged rod of length L at a distance x on its perpendicular bisector
We need to calculate the electric field
Using formula of electric field intensity

Where, Q = charge on the rod
The force is on the charged bead of charge q placed in the electric field of field strength E
Using formula of force

Put the value into the formula

We need to calculate the total charge on the rod

Put the value into the formula



Hence, The total charge on the rod is 47.8 nC.
Answer:
ball clears the net
Explanation:
= initial speed of launch of the ball = 20 ms^{-1}
= angle of launch = 5 deg
Consider the motion of the ball along the horizontal direction
= initial velocity = 
= time of travel
= horizontal displacement of the ball to reach the net = 7 m
Since there is no acceleration along the horizontal direction, we have
Eq-1
Consider the motion of the ball along the vertical direction
= initial velocity = 
= time of travel
= Initial position of the ball at the time of launch = 2 m
= Final position of the ball at time "t"
= acceleration in down direction = - 9.8 ms⁻²
Along the vertical direction , position at any time is given as

Since Y > 1 m
hence the ball clears the net