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Sever21 [200]
2 years ago
14

An object is attached to a hanging unstretched ideal and massless spring and slowly lowered to its equilibrium position, a dista

nce of 6.4 cm below the starting point. If instead of having been lowered slowly the object was dropped from rest, how far then would it then stretch the spring at maximum elongation?
Physics
1 answer:
Llana [10]2 years ago
6 0

Answer:

        h = 12.8 cm

Explanation:

from the equation we are given the following:

distance = 6.4 cm

  • when the object is being lowered the weight is equal to the spring force

        weight = spring force

         mg = ky ... equation 1

  • potential energy to stretch a spring = work done by the spring

        mgh = 0.5 x k x h^{2} ....equation 2

  • substituting equation 1 into equation 2

                kyh =  0.5 x k x h^{2}

                y =  0.5 x h

                2y = h

  • where y = 6.4 , the maximum elonf=gation becomes

          h = 2 x 6.4 = 12.8 cm

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Olin [163]

Answer:

The correct answer is option 'd': The frequency decreases and the intensity of the sound decreases.

Explanation:

1) <u>Effect on Frequency </u>

According to Doppler's effect of sound we have

for a source of sound moving away from the observer the relation between the observed and the original frequency is given by

f_{app}=\frac{c-v_{rec}}{c+v_{s}}\times f_{original}

where

c = speed of sound in air

v_{rec} is the velocity of observer of sound

v_{s} is the velocity of source of sound

f_{o} is the original frequency of sound

As we see the ratio is less than 1 thus the frequency of sound that the observer receives is less than that of source.

2) <u>Effect on Intensity:</u>

At a distance 'r' from source emitting a wave of Power 'P' is given by

I=\frac{P}{4\pi r^{2}}

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3 0
2 years ago
Water is boiled in a pan on a stove at sea level. During 10 min of boiling, it is observed that 200 g of water has evaporated. D
Ymorist [56]

Answer : The rate of heat transfer to the water is, 37.92 kJ/min

Explanation : Given,

Time = 10 min

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Now put all the given values in the above formula, we get:

Q=\frac{200g\times (2230-334)J/g}{10min}

Q=37920J/min=37.92kJ/min

Thus, the rate of heat transfer to the water is, 37.92 kJ/min

4 0
2 years ago
Compared to the resistivity of a 0.4-meter length of 1-millimeter-diameter copper wire at 0 degrees Celsius, the resistivity of
Mazyrski [523]

Answer:

Resistivity of both wires are same

Explanation:

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1mm=10^{-3} m

l_2=0.8 m

d_2=1mm

r_2=0.5\times 10^{-3} m

Temperature in each case is same.

Area of each wire,A_1=A_2=A=\pi r^2=\pi (0.5\times 10^{-3})^2m^2

Resistivity is the property of material due to which it offers resistance to the flow of current.

Resistivity of material depends upon the temperature and material by which it is made.

It does not depends upon the length of object.

Therefore, the resistivity of both wires of different length  are same.

3 0
2 years ago
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Calculate the wavelength of a neutron that has a velocity of 200. cm/s. (the mass of a neutron = 1.675 × 10–27 kg and h = 6.63 ×
Licemer1 [7]
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6 0
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natita [175]

Answer:

Explanation:

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b )

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5 0
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