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Anestetic [448]

2 years ago

5

To make the jump, Neo and Morpheus have pushed against their respective launch points with their legs applying a _____ to the la

unch points. distance dimension equilibrium force

1 answer:

ra1l [238]2 years ago

7 0

Force, newtons 3rd law of motion stated for every action there is an equal and opposite reaction

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Astronauts in the International Space Station must work out every day to counteract the effects of weightlessness. Researchers h

Snowcat [4.5K]

Answer:

33.725 rpm

Explanation:

The relationship between rotational speed in radians per second and acceleration is ...

$\omega=\sqrt{\dfrac{a}{r}}$

We want the rotation rate in RPM, so we need the conversion ...

$\text{RPM}=\dfrac{\text{rad}}{\text{s}}\cdot\dfrac{1\,\text{rev}}{2\pi\,\text{rad}}\cdot\dfrac{60\,\text{s}}{1\,\text{min}}$

Then the required rotational speed in RPM is ...

$RPM=\sqrt{\dfrac{a}{r}}\cdot\dfrac{30}{\pi}=\dfrac{30}{\pi}\sqrt{\dfrac{1.4\cdot 9.8}{1.1}}\approx 33.725$

The rotation rate needs to be about 33.7 rpm to give an acceleration of 1.4g at the astronaut's feet.

5 0

2 years ago

Calculate the force a 70.0-kg high jumper must exert on the ground to produce an upward acceleration 4.00 times the acceleration

worty [1.4K]

Answer:

3433.5 N

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

m = Mass of person = 70 kg

According to the question

a = Acceleration

$4g=4\times 9.81\\\Rightarrow a=39.24\ m/s^2$

Balancing the forces we have

$F-w=ma\\\Rightarrow F=ma+w\\\Rightarrow F=ma+mg\\\Rightarrow F=m(a+g)\\\Rightarrow F=70(39.24+9.81)\\\Rightarrow F=3433.5\ N$

The required force is 3433.5 N

3 0

2 years ago

A FBD of a rocket launching into space should include:

Vladimir [108]

Answer:

Explanation:

the force of the rocket engine pushing it up, the force of gravity pulling it down, maybe some force of air resistance as the rocket goes fast, hmmm Free Body Diagrams (FBD) should have any and all forces on the model, unless they are negligible . or so slight they really make little difference in the total outcome.

3 0

1 year ago

A biker travels at an average speed of 18 km/hr along a 0.30 km straight segment of a bike path. How much time (in hours) does t

lawyer [7]

Answer: 0.016 h

Explanation:

$\text{Average speed} = \frac{\text {Total Distance}}{\text {total time taken}}$

It is given that, biker has an average speed = 18 km/h

Total distance traveled = 0.30 km

Therefore, time taken by biker to travel this distance:

$\Rightarrow \text{total time taken} = \frac{0.30 km}{18 km/h}=0.016 h$

Thus, the biker takes 0.016 hours to travel the segment of 0.30 km at an average speed of 18 km/h.

7 0

2 years ago

A football player kicks a football downfield. The height of the football increases until it reaches a maximum height of 15 yards

Trava [24]

Answer:

kick 1 has travelled 15 + 15 = 30 yards before hitting the ground

so kick 2 travels 25 + 25 = 50 yards before hitting the ground

first kick reached 8 yards and 2nd kick reached 20 yards

Explanation:

1st kick travelled 15 yards to reach maximum height of 8 yards

so, it has travelled 15 + 15 = 30 yards before hitting the ground

2nd kick is given by the equation

y (x) = -0.032x(x - 50)

$Y = 1.6 X - 0.032x^2$

we know that maximum height occurs is given as

$x = -\frac{b}{2a}$

$y =- \frac{1.6}{2(-0.032)} = 25$

and maximum height is

$y = 1.6\times 25 - 0.032\times 25^2$

y = 20

so kick 2 travels 25 + 25 = 50 yards before hitting the ground

first kick reached 8 yards and 2nd kick reached 20 yards

8 0

2 years ago

Read 2 more answers