Given
m1(mass of red bumper): 225 Kg
m2 (mass of blue bumper): 180 Kg
m3(mass of green bumper):150 Kg
v1 (velocity of red bumper): 3.0 m/s
v2 (final velocity of the combined bumpers): ?
The law of conservation of momentum states that when two bodies collide with each other, the momentum of the two bodies before the collision is equal to the momentum after the collision. This can be mathemetaically represented as below:
Pa= Pb
Where Pa is the momentum before collision and Pb is the momentum after collision.
Now applying this law for the above problem we get
Momentum before collision= momentum after collision.
Momentum before collision = (m1+m2) x v1 =(225+180)x 3 = 1215 Kgm/s
Momentum after collision = (m1+m2+m3) x v2 =(225+180+150)x v2
=555v2
Now we know that Momentum before collision= momentum after collision.
Hence we get
1215 = 555 v2
v2 = 2.188 m/s
Hence the velocity of the combined bumper cars is 2.188 m/s
Answer:
D40 = 2.56 × D25
so number is 2.56 multiple of stopping distance @ 25 mph
Explanation:
given data
speed = 40 miles / hour
distance = D40
speed limit = 25 miles / hour
distance = D25
to find out
express number a multiple of stopping distance @ 25 mph
solution
we know here stopping distance is directly proportional to (speed)²
so here speed ratio is
initial speed = 
so initial speed = 1.6
so
stopping distance increase = (1.6)²
= (1.6)²
= 2.56
so here
D40 = 2.56 × D25
so number is 2.56 multiple of stopping distance @ 25 mph
V = u + a*t = 1100ft/s + (1000*10) ft/s = 11100 ft/s
Answer is <span>11,100 ft/s </span>
