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adoni [48]
2 years ago
8

Suppose you have designed a new thermometer called the x thermometer. on the x scale the boiling point of water is 129 ∘x and th

e freezing point of water is 12 ∘x. part a at what temperature are the readings on the fahrenheit and x thermometers the same? express your answer using two significant figures.
Physics
1 answer:
gladu [14]2 years ago
8 0

For any temperature scale the ratio of difference of temperature will be same

so we can write

\frac{T^ox - 12^ox}{129^ox - 12^ox} = \frac{T^of - 32^of}{212^of - 32^of}

now given that in both scales the temperature must be same

\frac{T^ox - 12^ox}{117^ox} = \frac{T^of - 32^of}{180^of}

T - 12 = 0.65 (T - 32)

0.35T = -8.8

T = -25.14 ^ox

<em>so at above temperature both scales will have same temperature</em>

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A stock person at the local grocery store has a job consisting of the following five segments:
vaieri [72.5K]

Answer:

B

Explanation:

Work done can be said to be positive if the applied force has a component to be in the direction of the displacement and when the angle between the applied force and displacement is positive.

In 1 and 2 work done is positive

6 0
2 years ago
_____ discovered that light also showed properties commonly found in waves.
Bad White [126]
Through the work of Max Planck<span>, Einstein, </span>Louis de Broglie<span>, </span>Arthur Compton<span>, </span>Niels Bohr<span>, current scientific theory holds that all particles also have a wave nature (and vice versa).</span>
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An electron moving at right angles to a 0.1 T magnetic field experiences an acceleration of 6 × 1015 m.s-2. What is the speed of
GaryK [48]

Explanation:

It is given that,

Magnetic field, B = 0.1 T

Acceleration, a=6\times 10^{15}\ m/s^2

Charge on electron, q=1.6\times 10^{-19}\ C    

Mass of electron, m=9.1\times 10^{-31}\ kg    

(a) The force acting on the electron when it is accelerated is, F = ma

The force acting on the electron when it is in magnetic field, F=qvB\ sin\theta

Here, \theta=90

So, ma=qvB

Where

v is the velocity of the electron

B is the magnetic field

v=\dfrac{ma}{qB}

v=\dfrac{9.1\times 10^{-31}\ kg\times 6\times 10^{15}\ m/s^2}{1.6\times 10^{-19}\ C\times 0.1\ T}

v = 341250  m/s

or

v=3.41\times 10^5\ m/s

So, the speed of the electron is 3.41\times 10^5\ m/s

(b) In 1 ns, the speed of the electron remains the same as the force is perpendicular to the cross product of velocity and the magnetic field.

7 0
2 years ago
A square is 1.0 m on a side. Point charges of +4.0 μC are placed in two diagonally opposite corners. In the other two corners ar
finlep [7]

Answer:

<em>B) 1.0 × 10^5 V</em>

Explanation:

<u>Electric Potential Due To Point Charges </u>

The electric potential produced from a point charge Q at a distance r from the charge is

\displaystyle V=k\frac{Q}{r}

The total electric potential for a system of point charges is equal to the sum of their individual potentials. This is a scalar sum, so direction is not relevant.

We must compute the total electric potential in the center of the square. We need to know the distance from all the corners to the center. The diagonal of the square is

d=\sqrt2 a

where a is the length of the side.

The distance from any corner to the center is half the diagonal, thus

\displaystyle r=\frac{d}{2}=\frac{a}{\sqrt{2}}

\displaystyle r=\frac{1}{\sqrt{2}}=0.707\ m

The total potential is  

V_t=V_1+V_2+V_3+V_4

Where V1 and V2 are produced by the +4\mu C charges and V3 and V4 are produced by the two opposite charges of \pm 3\mu\ C. Since all the distances are equal, and the charges producing V3 and V4 are opposite, V3 and V4 cancel each other. We only need to compute V1 or V2, since they are equal, but they won't cancel.

\displaystyle V_1=V_2=k\frac{Q}{r}=9\times 10^9 \frac{4\times 10^{-6}}{0.707}

V_1=V_2=50912\ V

The total potential is

V_t=50912\ V+50912\ V=1\times 10^5\ V

\boxed{V_t=1\times 10^5\ V}

6 0
2 years ago
13. A diver swims to a depth of 3.2 m in a freshwater lake. What is the increase in the force pushing in on her eardrum, compare
Gnoma [55]

Answer:

1.88 N

Explanation:

h = 3.2 m, A = 0.6 cm^2 = 0.6 x 10^-4 m^2

density of water, d = 1000 kg/m^3, g = 9.8 m/s^2

Pressure at depth h, P = h x d x g = 3.2 x 1000 x 9.8 = 31.36 x 10^3 Pa

Force = pressure x Area = 31.36 x 10^3 x 0.6 x 10^-4 = 1.88 N

Thus, the force on ear drum is 1.88 N.

6 0
2 years ago
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