Calculate the weight of the table through the equation,
W = mg
where W is the weight, m is the mass, and g is the acceleration due to gravity. Substituting the known values,
W = (0.44 kg)(9.8 m/s²)
<em>W = 4.312 N</em>
The components of this weight can be calculated through the equation,
Wx = W(sin θ)
and Wy = W(cos θ)
x - component:
Wx = W(sin θ)
Substituting,
Wx = (4.312 N)(sin 150°) = <em>2.156 N</em>
Wy = (4.312 N)(cos 150°) =<em> -3.734 N</em>
Answer:
The water will flow at a speed of 3,884 m/s
Explanation:
Torricelli's equation
v = 
*v = liquid velocity at the exit of the hole
g = gravity acceleration
h = distance from the surface of the liquid to the center of the hole.
v =
= 3,884 m/s
Answer:
0.68 m
Explanation:
α = dL / L1*(dT)
dL = L1(dT) * α
Initial length, L1 = 100
Chang in Length =dL
α linear expansivity ; dL = change in length ; dT = change in temperature ; L1 = initial length
α of iron rod = 1.13 * 10^-5 k
dL = 100(40 - 10) * 1.13 * 10^-5
dL = 100(30) * 1.13 * 10^-5
dL = 3000 * 1.13 * 10^-5
dL = 3390 * 10^-5
dL = 0.0339 m
Error :
Distance measured = 2km = (2 * 1000) = 2000m
[Distance measured / (initial length + change in length)] × change in length
Error = (2000 / (100 + 0.0339)) * 0.0339
Error = (2000 / 100.0339) * 0.0339
Error = 19.993222 * 0.0339
Error = 0.6777702
Error = 0.68 m
Answer:
1340.2MW
Explanation:
Hi!
To solve this problem follow the steps below!
1 finds the maximum maximum power, using the hydraulic power equation which is the product of the flow rate by height by the specific weight of fluid
W=αhQ
α=specific weight for water =9.81KN/m^3
h=height=220m
Q=flow=690m^3/s
W=(690)(220)(9.81)=1489158Kw=1489.16MW
2. Taking into account that the generator has a 90% efficiency, Find the real power by multiplying the ideal power by the efficiency of the electric generator
Wr=(0.9)(1489.16MW)=1340.2MW
the maximum possible electric power output is 1340.2MW