answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
iogann1982 [59]
2 years ago
9

A man is standing on a platform that is connected to a pulley arrangement, as the drawing shows. By pulling upward on the rope w

ith a force the man can raise the platform and himself. The total mass of the man plus the platform is 113 kg. What pulling force should the man apply to create an upward acceleration of 1.20 m/s2?

Physics
1 answer:
leonid [27]2 years ago
8 0

Answer:

The pulling force that the man should apply to create an upward acceleration of 1.20m/s^{2} is P=621.5N

Explanation:

Hi

As it shows in the drawing at the end, we have that the total mass of the man plus the platform is 113 kg, then the force downward W is W=mg=113Kg*9.8m/s^{2}=1107.4N.

Due the man needs to do a pulling force upward capable of lifting himself and the platform with an acceleration of 1.20m/s^{2}, this force should create an acceleration greater than gravity by 1.20m/s^{2}. then a_{up}=g+1.2m/s^{2}=9.8m/s^{2}+1.2m/s^{2}=11m/s^{2}. Therefore the force should be P_{up}=ma_{up}=113kg*11m/s^{2}=1243N.

Finally, as we have a pulley arrangement connected to the platform, it gives the man a mechanical advantage, so he has to do only half of that upward force

, therefore P=\frac{1243N}{2}=621.5N.

You might be interested in
Some gliders are launched from the ground by means of a winch, which rapidly reels in a towing cable attached to the glider. Wha
aliina [53]

Answer:

P=627.47W

Explanation:

To solve this problem we have to take into account, that the work done by the winch is

W=Fh

the force, at least must equal the gravitational force

F=Mg=(156kg)(9.8\frac{m}{s^2})=1258.8N

with force the tension in the cable makes the winch go up.

The work done is

W=(1258.8N)(58.0m)=73010.4J

To calculate the power we need to know what is the time t. But first we have to compute the acceleration

The acceleration will be

v_f^2=v_0+2ah\\a=\frac{v_f^2}{2h}=\frac{(24.9\frac{m}{s})}{2(58.0m)}=0.214\frac{m}{s^2}

and the time t

v_f=v_0+at\\t=\frac{v_f}{a}=116.35s

The power will be

P=\frac{W}{t}=\frac{73010.4J}{116.35s}=627.47W

HOPE THIS HELPS!!

6 0
2 years ago
In this lab you will use a cart and track to explore various aspects of motion. You will measure and record the time it takes th
Keith_Richards [23]

It is given that by using track and cart we can record the time and the distance travelled and also the speed of the cart can be recorded. With all this data we can solve questions on the laws of motion.  

Like using the first law of motion we can determine the force of gravity acting on the cart that has moved a certain distance and the velocity or the speed of card has already been registered and since time is known putting the values in formula would help us calculate the gravitational pull acting on cart.

3 0
2 years ago
Read 2 more answers
The lighting needs of a storage room are being met by six fluorescent light fixtures, each fixture containing four lamps rated a
Amanda [17]

Answer:

amount of energy  = 4730.4 kWh/yr

amount of money = 520.34 per year

payback period = 0.188 year

Explanation:

given data

light fixtures = 6

lamp = 4

power = 60 W

average use = 3 h a day

price of electricity = $0.11/kWh

to find out

the amount of energy and money that will be saved and simple payback period if the purchase price of the sensor is $32 and it takes 1 h to install it at a cost of $66

solution

we find energy saving by difference in time the light were

ΔE = no of fixture × number of lamp × power of each lamp × Δt

ΔE is amount of energy save and Δt is time difference

so

ΔE = 6 × 4 × 365 ( 12 - 9 )

ΔE = 4730.4 kWh/yr

and

money saving find out by energy saving and unit cost that i s

ΔM = ΔE × Munit

ΔM = 4730.4 × 0.11

ΔM = 520.34 per year

and

payback period is calculate as

payback period = \frac{excess initial cost}{\Delta M}

payback period = \frac{32 + 66}{520.34}

payback period = 0.188 year

8 0
2 years ago
4. While broadcasting a football game, the announcer exclaimed, "I can't believe it. Carl James just scored a touchdown. That's
Zielflug [23.3K]
D. Carl doesnt score touchdowns very often.
7 0
2 years ago
Read 2 more answers
A helicopter travels west at 80 mph. It is moving above a car traveling on a highway at 80 mph. Given this information, you can
gavmur [86]

Answer:

d. at the same velocity

Explanation:

I will assume the car is also travelling westward because it was stated that the helicopter was moving above the car. In that case, it depends where the observer is. If the observer is in the car, the helicopter would look like it is standing still ( because both objects have the same velocity). If the observer is on the side of the road, both objects would be travelling at the same velocity. Also recall that, velocity is a vector quantity; it is direction-aware. Velocity is the rate at which the position changes but speed is the rate at which object covers distance and it is not direction wise. Hence velocity is the best option.

5 0
2 years ago
Other questions:
  • Object A with a mass of 500 kilograms hits stationary object B with a mass of 920 kilograms. If the collision is elastic, what h
    14·1 answer
  • For what value of the ratio r/a of plate radius to separation between the plates does the electric field at the point x=a/2 on t
    15·1 answer
  • Image that the radiation emitted by the nitrogen at a frequency of 8.88×1014 Hz is absorbed by an electron in a molecule of meth
    9·2 answers
  • platform diving in the olympic games takes place at two heights: 5 meters and 10 meters. What is the velocity of a diver enterin
    5·1 answer
  • The Bohr model of the hydrogen atom pictures the electron as a tiny particle moving in a circular orbit about a stationary proto
    6·1 answer
  • When an automobile rounds a curve at high speed, the loading (weight distribution) on the wheels is markedly changed. For suffi-
    9·1 answer
  • An object initially at rest experiences a constant horizontal acceleration due to the action of a resultant force applied for 10
    15·1 answer
  • A 0.65-T magnetic field is perpendicular to a circular loop of wire with 73 turns and a radius of 18 cm. If the magnetic field i
    5·1 answer
  • Calculate the percent error of the distance to the moon.
    13·1 answer
  • 1. The mass of the Earth is 81 times the mass of the Moon. Using Newton's Law of Gravity, what would the effect of gravitation b
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!