For this case, what we can do is use the Pythagorean theorem to find the magnitude of the displacement of the car.
We have then

From here, we clear the value of d.
We have then:

Rewriting:
Answer:
The magnitude of the car's displacement is:
d = 20 miles
Let loudness be L, distance be d, and k be the constant of variation such that the equation that would best represent the given above is,
L = k/(d^2)
For Case 1,
L1 = k/(d1^2)
For Case 2,
L2 = k/((d1/4)^2)
For k to be equal, L1 = 16L2.
Therefore, the loudness at your friend's position is 16 times that of yours.
Answer:
335°C
Explanation:
Heat gained or lost is:
q = m C ΔT
where m is the mass, C is the specific heat capacity, and ΔT is the change in temperature.
Heat gained by the water = heat lost by the copper
mw Cw ΔTw = mc Cc ΔTc
The water and copper reach the same final temperature, so:
mw Cw (T - Tw) = mc Cc (Tc - T)
Given:
mw = 390 g
Cw = 4.186 J/g/°C
Tw = 22.6°C
mc = 248 g
Cc = 0.386 J/g/°C
T = 39.9°C
Find: Tc
(390) (4.186) (39.9 - 22.6) = (248) (0.386) (Tc - 39.9)
Tc = 335
Answer:
529.15 m/s
Explanation:
h = Maximum height = 70000 m
g = Acceleration due to gravity = 2 m/s²
m = Mass of sulfur
As the potential and kinetic energies are conserved

The speed with which the liquid sulfur left the volcano is 529.15 m/s
Answer:

Explanation:
Given:
- initial gauge pressure in the container,

- atmospheric pressure at sea level,

- initial volume,

- maximum pressure difference bearable by the container,

- density of the air,

- density of sea water,

<u>The relation between the change in pressure with height is given as:</u>

where:
dz = height in the atmosphere
= standard value of gravity
<em>Now putting the respective values:</em>



Is the maximum height above the ground that the container can be lifted before bursting. (<em>Since the density of air and the density of sea water are assumed to be constant.</em>)