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AveGali [126]
2 years ago
9

Which economic idea did Adam Smith promote in The Wealth of Nations?

Physics
2 answers:
alekssr [168]2 years ago
5 0

Answer:business should be free to operate without government regulation

Explanation:apex

7nadin3 [17]2 years ago
4 0

Answer: economies are the strongest when workers have specialized skills

Explanation:

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A cliff diver running 3.60 m/s dives out horizontally from the edge of a vertical cliff and reaches the water below 2.00 s later
mart [117]

Explanation:

It is given that,

The horizontal speed of a cliff diver, v_x=3.6\ m/s

It reaches the water below 2.00 s later, t = 2 s

Let d_x is the distance where the diver hit the water. It can be calculated as follows :

d_x=v_x\times t\\\\=3.6\times 2\\\\=7.2\ m

Let d_y is the height of the cliff. It can be calculated using second equation of motion as follows :

d_y=u_yt+\dfrac{1}{2}gt^2\\\\d_y=\dfrac{1}{2}\times 9.8\times 2^2\\\\=19.6\ m

So, the cliff is 19.6 m high and it will hit the water at a distance of 19.6 m.

8 0
1 year ago
After an eye examination, you put some eyedrops on your sensitive eyes. The cornea (the front part of the eye) has an index of r
mina [271]

Answer:

t = 103.45 n m

Explanation:

given,

refractive index of cornea = 1.38

refractive index of eye drop = 1.45

wavelength of refractive index = 600 nm

refractive index of eye drop is greater than refractive index of cornea and the air.

Formula used in this case

for constructive interference

2 n t = (m + \dfrac{1}{2})\lambda

At m = 0 for the minimum thickness, so

2\times 1.45 \times t = (0 + 0.5)\times 600

2.9 \times t =300

t =\dfrac{300}{2.9}

t = 103.45 n m

the minimum thickness of the film of eyedrops t = 103.45 n m

6 0
2 years ago
A spaceship of mass 8600 kg is returning to Earth with its engine turned off. Consider only the gravitational field of Earth. Le
Katyanochek1 [597]

Answer:

\Delta KE = 4.20\times 10^{13}\ J

Explanation:

given,

mass of spaceship(m) = 8600 Kg

Mass of earth = 5.972 x 10²⁴ Kg

position of movement of space ship

R₁ = 7300 Km

R₂ = 6700 Km

the kinetic energy of the spaceship increases by = ?

Increase in Kinetic energy = decrease in potential energy

    \Delta KE = GMm (\dfrac{1}{R_2}-\dfrac{1}{R_1})

    \Delta KE = GMm (\dfrac{R_1-R_2}{R_2R_1})

    \Delta KE = 6.67 \times 10^{-11}\times 5.972 \times 10^{24}\times 8600 (\dfrac{7300 - 6700}{7300 \times 6700})

    \Delta KE = 6.67 \times 10^{-11}\times 5.972 \times 10^{24}\times 8600 (\dfrac{600}{48910000})

    \Delta KE = 4.20\times 10^{13}\ J

5 0
2 years ago
Study the diagram and calculate the effort required to balance the load​
Lisa [10]

Answer:

Solution given;

load =600N

effort=?

load distance: 0.6m

effort distance;2.6m

we have

load *load distance :effort *effort distance

0.6*600=effort *2.6

360/2.6=effort

effort:138.46N

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6 0
2 years ago
a ford is traveling with a speed of 15m/s and is 200 meters ahead of a Chevy that is traveling in the same direction but at a sp
Andru [333]
Make an equation for both.
Ford= 15t+200
Chevy=20t
Now you must set them equal and solve for time t. Giving you 40 seconds. Now plug that in to the chevy equation to get 800 meters.
3 0
2 years ago
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