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Lana71 [14]
2 years ago
8

A carmaker has designed a car that can reach a maximum acceleration of 12 meters/second2. The car’s mass is 1,515 kilograms. Ass

uming the same engine is used, what should the car’s mass be if the carmaker wants to reach an acceleration of 15 meters/second2? Use F = ma.
A 1,212 kg
B 1,335 kg
C1,466 kg
D 1,515 kg
D 1,894 kg
Physics
1 answer:
Vlada [557]2 years ago
6 0
1) 15 / 12 = 1.25 ratio
2) to increase acceleration  1.25 times (with same F, or same engine) you have to lower mass 1.25 times
3) 1515/1.25 = 1212 kg

choose A

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Two resistors have resistances R1= ( 24+- 0.5)ohm and R2 = (8 +-0.3)ohm . Calculate the absolute error and the percentage relati
zysi [14]

Answer:

Absolute error=0.006

Percentage Relative error=0.6

Explanation:

The resistors have resistance of 24 ohm and 8 ohm.

The change in resistance is 0.5 and 0.3 ohm respectively.

Relative error for parallel combination of resistors is

= dR/R²

= dR1/R1² + dR2/R2²

= 0.5/(24)² + 0.3/(8)²

= 0.5/ 24*24 + 0.3/ 64

= 0.5/576+0.3/ 64

= 32 + 172.8/ 36,864

=204.8/ 36,864=0.0055

=0.006

Percentage error =Relative error *100

= 0.006* 100 = 0.6

8 0
2 years ago
A mass is tied to a string and swung in a horizontal circle with a constant angular speed. show answer No Attempt If this speed
Liono4ka [1.6K]

Answer:

The tension in the string is quadrupled i.e. increased by a factor of 4.

Explanation:

The tension in the string is the centripetal force. This force is given by

F = \dfrac{mv^2}{r}

m is the mass, v is the velocity and r is the radius.

It follows that F \propto v^2, provided m and r are constant.

When v is doubled, the new force, F_1, is

F_1 = \dfrac{m(2v)^2}{r} = \dfrac{4mv^2}{r} = 4\dfrac{mv^2}{r} = 4F

Hence, the tension in the string is quadrupled.

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2 years ago
"if a stream flow measures 12 meters in 60 seconds, what is the stream's average rate of flow?"
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Absorbance measurements in the range of a = 0.3-2 are considered the most accurate. why would absorbance measurements of 0.05 an
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Please provide the choices to select the possible choices.
6 0
1 year ago
For a metal that has an electrical conductivity of 7.1 x 107 (Ω-m)-1, do the following: (a) Calculate the resistance (in Ω) of a
jonny [76]

Answer:

(a) 0.0178 Ω

(b) 3.4 A

(c) 6.4 x 10⁵ A/m²

(d) 9.01 x 10⁻³ V/m

Explanation:

(a)

σ = Electrical conductivity = 7.1 x 10⁷ Ω-m⁻¹

d = diameter of the wire = 2.6 mm = 2.6 x 10⁻³ m

Area of cross-section of the wire is given as

A = (0.25) π d²

A = (0.25) (3.14) (2.6 x 10⁻³)²

A = 5.3 x 10⁻⁶ m²

L = length of the wire = 6.7 m

Resistance of the wire is given as

R=\frac{L}{A\sigma }

R=\frac{6.7}{(5.3\times10^{-6})(7.1\times10^{7}) }

R = 0.0178 Ω

(b)

V = potential drop across the ends of wire = 0.060 volts

i = current flowing in the wire

Using ohm's law, current flowing is given as

i = \frac{V}{R}

i = \frac{0.060}{0.0178}

i = 3.4 A

(c)

Current density is given as

J = \frac{i}{A}

J = \frac{3.4}{5.3\times10^{-6}}

J = 6.4 x 10⁵ A/m²

(d)

Magnitude of electric field is given as

E = \frac{J}{\sigma }

E = \frac{6.4 \times 10^{5}}{ 7.1 \times 10^{7}}

E = 9.01 x 10⁻³ V/m

5 0
2 years ago
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