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2 years ago

The wind blows a jay bird south with a force of 300 Newtons. The

Physics

1 answer:

adoni [48]2 years ago

6 0

Answer:

F = 316.22 N

Explanation:

Given that,

The wind blows a jay bird south with a force of 300 Newtons.

The jay bird flies north, against the wind, with a force of 100 newtons.

Both the forces are acting perpendicular to each other. The net force is given by the resultant of forces as follows :

$F=\sqrt{300^2+100^2} \\\\F=316.22\ N$

Hence, the net force on the jay bird is 316.22 N.

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A positive point charge Q is fixed on a very large horizontal frictionless tabletop. A second positive point charge q is release

Scilla [17]

Answer:

(A) As it moves farther and farther from Q, its speed will keep increasing.

Explanation:

When a positive charge Q is fixed on a horizontal frictionless tabletop and a second charge q is released near to it then according to the Coulombs law the force acting on it decreases with the square of the distance between them.

Mathematically:

$F=\frac{1}{4\pi.\epsilon_0} \times \frac{Q.q}{r^2}$

where:

r = distance between the charges

$\epsilon_0=$ permittivity of free space

By the Newtons' second law of motion if the we know that the acceleration is directly proportional to the force applied. So as the distance between the charges increases the its acceleration also decreases therefore now the charge feels less acceleration but still continues to accelerate with a fading magnitude.

7 0

2 years ago

A tennis player serves a tennis ball such that it is moving horizontally when it leaves the racquet. When the ball travels a hor

nalin [4]

Answer:

$u_x=38.13\ m/s$

Explanation:

Given that initially ball moves in the horizontal direction ,it means that the velocity in the vertical direction is zero.

Horizontal distance = 13 m

Vertical distance = 57 cm

Lets take time to cover 57 cm distance in vertical direction is t.

We know that g is the constant acceleration in the vertical direction so we can apply the equation of motion in the vertical direction.

$S=u_yt+\dfrac{1}{2}gt^2$

Here $u_y=0$

S= 57 cm

$0.57=0\times t+\dfrac{1}{2}\times 9.81\times t^2$

t=0.34 s

Now in the horizontal direction

$x=u_xt$

Here x=13 m

t= 0.34 s

$13=u_x\times 0.34$

$u_x=38.13\ m/s$

So the initial speed of ball is 38.13 m/s.

7 0

2 years ago

1. Suppose a tank filled with water has a liquid column with a height of 10 meters. If the area is 2 square meters (m²), what's

Anit [1.1K]

Answers:

1. Firstly, we have to define that Pressure $P$ is Force applied $F$ per unit area $A$ . It is mathematically expressed as follows:

$P=\frac{F}{A}$ (1)

The unit of P is Pascal (Pa) which is equivalent to $\frac{kg}{ms^{2}}$ and also equivalent to $\frac{N}{m^{2} }$

There is also another expression of the Pressure in which it is dependent on the density $d$ of the liquid, the height $h$ of the container and the gravity force $g$ :

$P=d*h*g$ (2)

In this problem the liquid is water, and its known density is approximately:

$d=1000kg/m^{3}$

So, we have to substitute the values in equation (2) to obtain the pressure (Being careful with the units):

$P=1000\frac{kg}{m^{3}}*10m*9.8\frac{m}{s^{2}}$

$P=98000Pa$

Then, we have to substitute this value in equation (1) and clear $F$ :

$F=P*A$

Finally:

$F=196000N$

2. For this problem, we will use equation (1) to find the Pressure. We already know the area $A$ and the force exerted by water in the container $F$ :

$P=\frac{F}{A}=\frac{900N}{3m^{2}}$

$P=300Pa$

3. In this case, equation (2) is the perfect way to find the hydrostatic pressure at any point at the bottom of the tank (be careful with the units):

$P=d*h*g$

$P=1000\frac{kg}{m^{3}}*7.5m*9.8\frac{m}{s^{2}}$

$P=73500Pa$

4. In this case, it's important to know that in fluids (in this case the water) the higher the fluid is, the lower the pressure. Then, if $P_{1}$ and $P_{2}$ are the respective pressures at the heights $h_{1}$ and $h_{2}$ , and knowing that the water density and the gravity force in this case are constants, we can use the following expression to solve this problem:

$P_{2}- P_{1} =d*g(h_{2}- h_{1})$ (3)

Where:

$P_{1}=1.5 kPa$ at $h_{1}=2m$

Note that $1kPa=1*1000 Pa$

And $P_{2}=?$ is unknown at a given height $h_{2}=6m$

Then, we have to substitute the values in equation (3) to find $P_{2}$ :

$P_{2}-1500Pa=1000\frac{kg}{m^{3}}*9.8\frac{m}{s^{2}} (6m-2m)$

Finally: $P_{2} =40700Pa$

5. In this case we have the area $A=0.75m^{2}$ and the mass of the piston $m=200kg$ , and we need to know the pressure $P$ .

We will use equation (1):

$P=\frac{F}{A}$

But, do you remember that above we stated that pressure is the force applied over an area?

Well, in this case we will use the following equation, in which the gravity force and the mass of a body are involved, to find $F$ :

$F=m*g=200kg*9.8\frac{m}{s^{2}}$

Then:

$F=1960N$

Now we can finally calculate $P$ :

$P=\frac{1960N}{0.75m^{2}}$

$P=2613.33Pa$

5 0

2 years ago

Read 2 more answers

Shareen performs a skit to model a method of charging. In the skit, a painter shakes her hand and gets paint on her.

Veseljchak [2.6K]

Answer:

It models conduction because the painter represents a charged object and the paint represents electrons that are transferred through contact.

Explanation:

Conduction phenomenon of charging is the process of charging in which two bodies are made in contact with each other so that charges are transferred due to potential difference of two bodies.

here we know that when hands are shake then it will have paint on it. so here due to hand shake the hands are in contact with charge particles and due to contact the electrons are transferred to the hand.

Now here we need to assume that charge of paint must be opposite that of the charge on the hand because only due to opposite charge attraction the paint must be transferred to the hand

SO here correct answer will be

It models conduction because the painter represents a charged object and the paint represents electrons that are transferred through contact.

5 0

2 years ago

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A scientist is examining an unknown solid. Which procedure would most likely help determine a chemical property of the substance

kifflom [539]

Answer:

b. exposing it to a flame to see if it catches on fire

Explanation:

The Procedure will most likely help to determine a chemical property of substance is : exposing material to a flame to see if it catches on fire Chemical property is the characteristic that a substance has that differentiate it from another substance. The most common charatcteristics that most scientists wanted to know are : - It's flammability - It's radioactivity - Its toxicity By throwing the object into fire, we will easily find out these 3 characteristics

Hence the correct answer is b. exposing it to a flame to see if it catches on fire.

3 0

2 years ago

Read 2 more answers