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pantera1 [17]
2 years ago
11

Argelia has a stack of schoolbooks sitting in the backseat of her car. When Argelia makes a sharp right turn, the books slide to

the left of the seat until they come to a rest against the car door. Explain why this happens.
Physics
2 answers:
mixer [17]2 years ago
8 0

Answer:

Sample Response: Before making the right turn, the books were moving in a straight line. As the turn was being made, the books continued moving in a straight line due to inertia. The books slid across the seat until the car door exerted a force on them that caused them to make the turn with the rest of the car.

Kaylis [27]2 years ago
4 0

Answer:

The books slide to the left due to inertia, and then they come to a rest due to the force applied by the car door.

Explanation:

The entire motion of the books can be explained by using the first two laws of Newton:

- 1st Newton's law (also called Law of Inertia): an object at rest stays at rest and an object in motion stays in motion with constant velocity if no unbalanced forces act on it

- 2nd Newton's law: when an object is acted upon unbalanced forces, an acceleration is induced in the motion of the object, according to the equation

F=ma

where F is the net force on the object, m is its mass and a is its acceleration.

Coming back to our problem:

- At the beginning, Argelia makes a sharp turn right. Due to the law of inertia, the books (which are not fixed to the car) continue their motion straight as it was before the curve: so, since the car is moving right, they appear to go the left of the car.

- When the books hit the car door, they stop moving due to the 2nd Newton's law: in fact, the car door applies an unbalanced force against the books, and as a result the books have a negative acceleration (=deceleration), so they slow down and eventually they stop.

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algol13
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miss Akunina [59]
Because weight W = M g, the ratio of weights equals the ratio of masses.

(M_m g)/ (M_w g) = [ (p^2 Man )/ (2 K_man)] / [ (p^2 Woman )/ (2 K_woman)

but p's are equal, so

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1 year ago
. Suppose you have a device that extracts energy from ocean breakers in direct proportion to their intensity. If the device prod
slava [35]

Answer:

4.988kW

Explanation:

According to the question, energy E extracted from the ocean breaker is directly proportional to the intensity I. It can be expressed mathematically as E ∝ I

E = kI where k is the constant of proportionality.

From the formula; k = E/I

This shows that increase in energy extracted will lead to increase in its intensity and vice versa.

If the device produces 10.0 kW of power on a day when the breakers are 1.20 m high

E = 10kW and I = 1.20m

k = 10/1.20

k = 8.33kW/m

To know how much energy E that will be produced when they are 0.600 m high, we will use the same formula

k = E/I where;

k = 8.33kW/m

I = 0.600m

E = kI

E = 8.33 × 0.6

E = 4.998kW

The device will produce energy of 4.998kW when they are 0.600m high.

3 0
1 year ago
Read 2 more answers
Why do you think scientists needed to invent a temperature scale, instead of deciding if things were hot or cold?
vlabodo [156]

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"Hot" and "cold" mean different things to different people, and may even mean different things to the same person at different times.

A person who grew up in Panama, and comes to visit Chicago in July, says it's cold.

A person who lives in Chicago, and goes to visit Jamaica in January, says it's hot.

A professional chef, following a recipe, can't just cook the steak until it's "hot inside". He needs a number, so he can cook it the same every time.

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1 year ago
A physicist is constructing a solenoid. She has a roll of insulated copper wire and a power supply. She winds a single layer of
Leni [432]

Answer:

P =105.44 W

Explanation:

Given that

D= 10 cm ,L= 60 cm

d= 0.1 cm ,B= 6.4 mT

ρ= 1.7 x 10⁻⁸ Ω · m

The number of turns N

N= L/d

N= 60/0.1 = 600 turns

Length of wire

Lc= πDN

Lc= 3.14 x 0.1 x 600

Lc=188.4 m

The magnetic filed given as

B=\dfrac{\mu_oNI}{L}

I=\dfrac{BL}{\mu_oN}

Now by putting the values

I=\dfrac{0.0064\times 0.6}{4\pi \times 10^{-7}\times 600}

I=5.09 A

The resistance R given as

R=\dfrac{\rho L_c}{A}

A=\dfrac{\pi}{4}\times d^2

A=\dfrac{\pi}{4}\times (0.1\times 10^{-2})^2

R=\dfrac{1.7\times 10^{-8} \times 188.4}{\dfrac{\pi}{4}\times (0.1\times 10^{-2})^2}

R=4.07 Ω

Power P

p =I²R

P= 5.09² x 4.07 W

P =105.44 W

5 0
2 years ago
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