Answer: a. F doubled
b. F reduced by one-quarter i.e
1/4*(F)
c. 1/9*(F)
d. F increased by a factor of 4 i.e 4*F
e. F reduces 3/4*(F)
Explanation: Coulombs law states the force F of attraction/repulsion experience by two charges qA and qB is directly proportional to thier product and inversely proportional to the square of distance d between them. That is
F = k*(qA*qB)/d²
a. If qA is doubled therefore the force is doubled since they are directly proportional.
b. If qA and qB are half, that means thier new product would be qA/2)*qB/2 =qA*qB/4
Which means the product of charge is divided by 4 so the force would be divided by 4 too since they are directly proportional.
c. If d is tripped that is multiplied by 3. From the formula new d would be (3*d)²=9d² but force is inversely proportional to d² so instead of multiplying by 9 the force will be divided by 9
d. If d is cut into half that is divided by 2. The new d would be (d/2)²=d²/4. So d² is divided by 4 so the force would be multiplied by 4
e. If qA is tripled that is multiplied by 3. F would be multiplied by 3 also, if at the same time d is doubled (2*d)²= 4*d² . Force would be divided by 4 at same time. So we have,
3/4*F
Answer:
Speed of water, v = 4.2 m/s
Explanation:
Given that,
Diameter of the tank, d = 17 cm
It is placed at a height of 90 cm, h = 0.9 m
We need to find the speed at which the water exits the tank through the hole. It can be calculated using the conservation of energy as :



v = 4.2 m/s
So, the speed of water at which the water exits the tank through the hole is 4.2 m/s. Hence, this is the required solution.
Answer:
1 ) Electrons are less massive than than atomic nuclei.
Explanation:
A positively charged body tends to attract negatively charged particle and repel positively charged particle. Neutral body consists of atoms which contain both positively charged particles ( electrons ) and negatively charged particles ( protons ). Electrons are small and light in weight . Both electrons and protons experience equal and opposite force by an external charged body but shift in electron is more because of their being comparatively lighter. So the body gets polarized due to uneven distribution of charge. This results into body getting attracted through the process of induction.
The answer would be . Since we are looking for the spring constant you would need to use the formula

. Then you'd substitute, for PEs and x.

Then solve. k=500n/m
Answer:
= 85.89 ° C
Explanation:
The linear thermal expansion process is given by
ΔL = L α ΔT
For the three-dimensional case, the expression takes the form
ΔV = V β ΔT
Let's apply this equation to our case
ΔV / V = -0.507% = -0.507 10-2
ΔT = (ΔV / V) 1 /β
ΔT = -0.507 10⁻² 1 / 1.15 10⁻³
ΔT = -4.409
–T₀ = 4,409
= T₀ - 4,409
= 90.3-4409
= 85.89 ° C