Question

Two swimmers begin a race and Swimmer A completes each length of the pool in 30 seconds, while Swimmer B completes each length in 40 seconds. How far ahead of Swimmer B will Swimmer A be after five minutes?

Answer 1

Answer:1.33 times

Explanation:

Given

A takes 30 sec to complete each length

While B takes 40 sec to complete each length

Let L be the Length of Swimming pool Length

and $V_a$ and $V_b$ be the length of A & B

Thus after 5 minutes A traveled

$x_a=\frac{L}{30}\times 5\times 60=10L$

$x_b=\frac{L}{40}\times 5\times 60=7.5L$

so A is 2.5L units ahead of B

A has traveled 1.33 times than B in 5 mins