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Ratling [72]
2 years ago
10

Consider heat transfer between two identical hot solid bodies and their environments. The first solid is dropped in a large cont

ainer filled with water, while the second one is allowed to cool naturally in the air. For which solid is the lumped system analysis more likely to be applicable? Why?
Physics
1 answer:
sergeinik [125]2 years ago
4 0
<h2>For Second Solid Lumped System is Applicabe</h2>

Explanation:

Considering heat transfer between two identical hot solid bodies and their environments -

  • If the first solid is dropped in a large container filled with water, while the second one is allowed to cool naturally in the air than for second solid, the lumped system analysis more likely to be applicable
  • The  reason is that a lumped system analysis is more likely to be applicable in the air than in water as the convection heat transfer coefficient so that the Biot number is less than or equal to 0.1 that is much smaller in air

Biot number = the ratio of conduction resistance within the body to convection resistance at the surface of the body

∴ For a lumped system analysis Biot number should be less than 0.1

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To determine the height of a flagpole, Abby throws a ball straight up and times it. She sees that the ball goes by the top of th
Kryger [21]

Answer:

H = 10.05 m

Explanation:

If the stone will reach the top position of flag pole at t = 0.5 s and t = 4.1 s

so here the total time of the motion above the top point of pole is given as

\Delta t = 4.1 - 0.5 = 3.6 s

now we have

\Delta t = \frac{2v}{g}

3.6 = \frac{2v}{9.8}

v = 17.64 m/s

so this is the speed at the top of flag pole

now we have

v_f - v_i = at

17.64 - v_i = (-9.8)(0.5)

v_i = 22.5 m/s

now the height of flag pole is given as

H = \frac{v_f + v_i}{2}t

H = \frac{22.5 + 17.64}{2} (0.5)

H = 10.05 m

5 0
2 years ago
The wavelength of some red light is 700.5 nm. what is the frequency of this red light?
Alborosie
The frequency of the red light is 428 terahertz. To get the value of the red light's frequency, use the formula F = velocity/wavelength. The velocity of light is 3.00 x 10^8 m/s. For easier computation, convert 700.5 nanometers to meter. 1 nanometer is equal to 1 x 10^-9 meters. 700.5 nanometers is equal to 7.005 x 10^-7 meters. Divide the velocity 3.00 x 10^8m/s by wavelength 7.005 x 10^-7 meters. The result will be 4.28 x 10^14 Hertz or 428 terahertz.
4 0
2 years ago
A boat moves through the sea.
sergiy2304 [10]

Answer:

dont you have to times it

Explanation:

4 0
2 years ago
You are driving to the grocery store at 20 m/s. You are 110m from an intersection when the traffic light turns red. Assume that
oksano4ka [1.4K]

As we know that reaction time will be

t = 0.50 s

so the distance moved by car in reaction time

d = vt

d = 20 \times 0.50

d = 10 m

now the distance remain after that from intersection point is given by

d = 110 - 10 = 100 m

So our distance from the intersection will be 100 m when we apply brakes

now this distance should be covered till the car will stop

so here we will have

v_f = 0

v_i = 20 m/s

now from kinematics equation we will have

v_f^2 - v_i^2 = 2 a d

0 - 20^2 = 2(a)100

a = \frac{-400}{200} = -2 m/s^2

so the acceleration required by brakes is -2 m/s/s

Now total time taken to stop the car after applying brakes will be given as

v_f - v_i = at

0 - 20 = -2 (t)

t = 10 s

total time to stop the car is given as

T = 10 s + 0.5 s = 10.5 s

3 0
2 years ago
The acceleration due to gravity at the north pole of Neptune is approximately 11.2 m/s2. Neptune has mass 1.02×1026 kg and radiu
larisa [96]

Answer: (a) The gravitational force on the object at the North Pole of Neptune is 51.7N

(b) The apparent weight of the object at Neptune's equator is 50.4N

Explanation: Please see the attachments below

5 0
2 years ago
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