Question

A typical machine tests the tensile strength of a sheet of material cut into a standard size of 5.00 centimeters wide by 10.0 centimeters long. The machine consists of one clamp that holds the entire width (5.00 centimeters) so that it hangs vertically. A second clamp is placed on the lower end of the object, to which a variable downward force is applied. The force is slowly increased until the object ruptures, and the breaking force is recorded.
A strip of aluminum foil with a thickness of 15.0 micrometers and matching the size recommendations of the machine is placed in the machine and tested. The force needed to rupture the foil is found to be 233 newtons. What is the tensile strength of the aluminum foil sample?

Answer 1

Answer:

Explanation:

tensile strength is stress that is needed to break the wire made of the material .

Here force required to break the sheet of material = 233 N

cross sectional area of the foil = breadth x thickness

= 5 x 10⁻² x 15 x 10⁻⁶ m²

= 75 x 10⁻⁸ m²

breaking stress = force / cross sectional area

= 233 / 75 x 10⁻⁸

= 3.1 x 10⁸ Pa .

Tensile strength = 3.1 x 10⁸ Pa .