Answer:
When the ball goes down its mechanical energy is conserved, ust before touching the ground all the energy is kinetic
When the ball touches the floor, energy has been converted into potential and heat, by the deformation of the ball.
Explanation:
When the ball goes down its mechanical energy is conserved, this is the power energy due to the height it is converted into kinetic energy to medicad that falls, just before touching the ground all the energy is kinetic.
When the ball touches the floor, the kinetic energy is not conserved, but if we define a system formed by the ball and the floor, the amount of movement is conserved, this being an inelastic shock, because the bla and the floor are stuck, so which energy has been converted into potential and energized and heat by the deformation of the ball.
Consequently all the mechanical energy that the ball brings before reaching the ground was converted into potential energy and heat during the crash.
Well we know acceleration from free fall due to gravity is 9.8m/s^2
Lay out
S = displacement is what we need
U
V = 1.5m/s
A = 9.8m/s2
T = 16.0s
Use the equation s=vt-1/2at^2
Where a = acceleration t= time and v= velocity
Sub in the values to get displacement or height from ground
= -1230.4 metres which would be positive as you’re measuring distance (scalar quantity) so it’s 1230.4 metres
Answer:
73.67 m
Explanation:
If projected straight up, we can work in 1 dimension, and we can use the following kinematic equations:
,
Where 
its our initial height, 
our initial speed, a the acceleration and t the time that has passed.
For our problem, the initial height its 0 meters, our initial speed its 38.0 m/s, the acceleration its the gravitational one ( g = 9.8 m/s^2), and the time its uknown.
We can plug this values in our equations, to obtain:
note that the acceleration point downwards, hence the minus sign.
Now, in the highest point, velocity must be zero, so, we can grab our second equation, and write:
and obtain:
Plugin this time on our first equation we find:
At the focal length of the mirror. The reason why is when parallel light rays hit the mirror, it converges at the focal point. So if we want parallel light rays, it would make sense to put it at the focal point.<span />
Answer:
a) 0.500 s
b) greater than 0.500 s
c) greater than 0.500 s
Explanation:
The time period of an oscillating spring-mass system is given by:
where, m is the mass and k is the spring constant.
a) As the period of oscillation does not depend on the distance by which the mass is pulled, the period would remain same as 0.500 s for the given system.
b) As the period varies inversely with the square root of spring constant, so with the decrease in the spring constant, the period would increase. So, the new period would be greater than 0.500 s.
c) As the period varies directly with the square root of mass, so with the increase in mass, the period will also increase. The new period will be greater than 0.500 s.
