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konstantin123 [22]
1 year ago
7

Some vehicles, like _____, have different rules for registration and renewal. A. trailers B. coupes C. sedans D. pickup trucks

Physics
1 answer:
ycow [4]1 year ago
7 0

Answer:

trailers

Explanation:

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A car is traveling at 20 meters/second and is brought to rest by applying brakes over a period of 4 seconds. What is its average
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 (u) = 20 m/s 
(v) = 0 m/s 
<span> (t) = 4 s 
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<span>0 = 20 + a(4) 

</span><span>4 x a = -20 
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so, the answer is <span>-5 m/s^2. or -5 meter per second</span>
8 0
2 years ago
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A quantity y is to be determined from the equation y=(px)/q^2
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4 0
1 year ago
: The truck is to be towed using two ropes. Determine the magnitudes of forces FA and FB acting on each rope in order to develop
Sholpan [36]

Answer:

Fa=774 N

Fb=346 N

Explanation:

We will solve this problem by equating forces on each axis.

  1. On x-axis let forces in positive x-direction be positive and forces in negative x-direction be negative
  2. On y-axis let forces in positive y-direction be positive and forces in negative y-direction be negative

While towing we know that car is mot moving in y-direction so net force in y-axis must be zero

⇒∑Fy=0

⇒Fa*sin(50)-Fb*sin(20)=0

⇒Fa*sin(50)=Fb*sin(20)

⇒Fa=2.24Fb

Given that resultant force on car is 950N in positive x-direction

⇒∑Fx=950  

⇒Fa*cos(20)+Fb*cos(50)=950

⇒2.24*Fb*cos(20)+Fb(50)=950

⇒Fb*(2.24*cos(20)+cos(50))=950

⇒Fb=\frac{950}{2.24*cos(20)+cos(50)}

⇒Fb=\frac{950}{2.24*0.94+0.64}

⇒ Fb=\frac{950}{2.75}=345.5

⇒Fa=2.24*Fb

      =2.24*345.5

      =773.93

Therefore approximately, Fa=774 N and Fb=346 N

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2 years ago
Specific agricultural uses of water are all of the following except _____. evaporation growing crops raising livestock cleaning
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Evaporation.............
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2 years ago
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A teacher sets up a stand carrying a convex lens of focal length 15 cm at 20.5 cm mark on the optical bench. She asks the studen
Brums [2.3K]
We get the clearest image if there is no magnification. When we have no magnification the image and real object have the same size.
If we look at the diagram that I  attached we can see that:
\frac{h_i}{h_0}=\frac{d_i}{d_0}
Two triangles that I marked are similar and from this we get:
\frac{h_i}{h_0}=\frac{d_i-f}{f}
The image and the object must have the same height so we get:
\frac{h_i}{h_0}=\frac{d_i-f}{f};h_i=h_0\\&#10;1=\frac{d_i-f}{f}\\&#10;d_i=2f
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S=20.5cm+2f=20.5+2\cdot 15cm=50.5cm

8 0
1 year ago
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