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kherson [118]
2 years ago
10

A transformer is to be used to provide power for a computer drive. The number of turns in the primary is 1000, and it delivers a

secondary current of 600 milliamperes (mA) at a secondary voltage of 8.0 V for the drive. A voltage of 400 volts is applied across the primary. What kind of transformer is this?a. step upb. Loadc. Step-Downd. AC
Physics
1 answer:
Yuri [45]2 years ago
3 0

Answer:

C.Step-Down

Explanation:

Given that

Number of turn in the primary N₁= 1000

Secondary current I₂= 600 mA

Secondary voltage V₂= 8 V

Primary voltage V₁= 400 V

From the above information we can say that output voltage is low compare to input voltage.

V₂ < V₁

We know that if

1 . V₂ < V₁  - Then transformer will be step down .

2. V₂ > V₁  - Then transfer will be step up .

Here

V₂ < V₁  ( 8 V < 400 V)

So the transformer is step down transformer.

C.Step-Down

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Answer:

Mass of shot (m) = 4 kg

Explanation:

Given:

Velocity (v) = 15 m/s

Mechanical kinetic energy (K.E) = 450 J

Find:

Mass of shot (m) = ?

Computation:

Mechanical kinetic energy (K.E) = 1/2mv²

Mechanical kinetic energy (K.E) = [1/2](m)(15)²

450 = [1/2](m)(15)²

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Mass of shot (m) = 4 kg

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Find an expression for the torsional constant k in terms of the moment of inertia I of the disk and the angular frequency ω of s
sasho [114]

Answer:

Explanation:

The general equation for the disk with moment of inertia I when given small angular displacement  \theta is given by

I\frac{\mathrm{d^2} \theta }{\mathrm{d} t^2}=-k\theta

\frac{\mathrm{d^2} \theta }{\mathrm{d} t^2}+\frac{k\theta }{I}=0

Replacing

\frac{k\theta }{I}=\omega ^2

where \omega is the angular frequency of oscillation

General solution for this Equation is given by

\theta =\theta _{max}\sin \left ( \omega t+\phi \right )

where \theta _{max}=maximum\ angular\ displacement

\phi =Phase\ difference

Thus K can be written as

k=I\omega ^2

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A 0.242 g sample of potassium is heated in oxygen. The result is 0.292 g of a crystalline compound. What is the formula of this
masha68 [24]

Answer:

Hello there Dude answer is B :D hope it helped mark me brainliest.

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2 years ago
A policeman kicks in a door with a force of 4500 N. What force does the door apply to the policeman’s leg?
Soloha48 [4]

Answer:

-4500 N

Source: Brainly

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You testify as an expert witness in a case involving an accident in which car A slid into the rear of car B, which was stopped a
bekas [8.4K]

Answer:

A) 12.08 m/s

B) 19.39 m/s

Explanation:

A) Down the hill, we will apply Newton’s second law of motion in the downward direction to get:

mg(sinθ) – F_k = ma

Where; F_k is frictional force due to kinetic friction given by the formula;

F_k = (μ_k) × F_n

F_n is normal force given by mgcosθ

Thus;

F_k = μ_k(mg cosθ)

We now have;

mg(sinθ) – μ_k(mg cosθ) = ma

Dividing through by m to get;

g(sinθ) – μ_k(g cosθ) = a

a = 9.8(sin 12.03) - 0.6(9.8 × cos 12.03)

a = -3.71 m/s²

We are told that distance d = 24.0 m and v_o = 18 m/s

Using newton's 3rd equation of motion, we have;

v = √(v_o² + 2ad)

v = √(18² + (2 × -3.71 × 24))

v = 12.08 m/s

B) Now, μ_k = 0.10

Thus;

a = 9.8(sin 12.03) - 0.1(9.8 × cos 12.03)

a = 1.08 m/s²

Using newton's 3rd equation of motion, we have;

v = √(v_o + 2ad)

v = √(18² + (2 × 1.08 × 24))

v = 19.39 m/s

6 0
2 years ago
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