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Artemon [7]
2 years ago
11

3.00 kg block moving 2.09 m/s right hits a 2.22 kg block moving 3.92 m/s left. afterwards, the 3.00 kg block moves 1.71 m/s left

. find the velocity of the 2.22 kg block afterwards
Physics
1 answer:
Sloan [31]2 years ago
6 0

Answer:

1.215 m/s to the right

Explanation:

The overall momentum of the system is conserved before and after collision.

Before the collision:

Momentum = 3.00*2.09 - 2.22*3.92 = -2.4324 (keep in mind that the motions are opposite in directions so they are supposed to have opposite signs. I chose leftward motion as negative and rightward motion as positive)

After the collision:

<h3>Momentum = -3.00*1.71 + 2.22*x;</h3>

Since momentum is conserved:

<h3>-3.00*1.71 +2.22x = -2.4324</h3>

Solve for x to find the velocity of the 2nd block.

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Answer:

Explanation:

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1. A diffraction grating with 5.000 x 103 lines/cm is used to examine the sodium
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A particle is in uniform circular motion. Assume a standard rtz coordinate system. If you deconstruct the net force acting on th
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Answer:

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Answer:

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