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stepladder [879]
2 years ago
13

Below are four statements about acceleration. Which statement is not correct? A Acceleration always involves changing speed. B C

hanging direction always involves acceleration. C Changing speed always involves acceleration. D Circular motion always involves acceleration.
Physics
1 answer:
True [87]2 years ago
6 0

Answer:

A. Acceleration always involves changing speed.

Explanation:

Acceleration is defined as the rate of change of velocity.

Velocity is a vector quantity and is defined as speed in a given direction. Therefore, when any or both of the components of velocity is changing with time, a body is said to be accelerating i.e. acceleration involves a change of speed or change in direction, or a change in both speed and direction.

Considering the statements:

A. Acceleration always involves changing speed is false because acceleration can occur when speed is constant but direction is changing.

B. Changing direction always involves acceleration is true because, a change in direction results in a change in velocity.

C Changing speed always involves acceleration is true because, changing speed results in a change in velocity.

D. Circular motion always involves acceleration is true because in circular motion the direction is always changing, and this results in a change in velocity

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<span>As it is descended from a vertical height h, The lost Potential Energy = Mgh The gained Kenetic Energy = (1/2)Mv^2; The rotational KE = (1/2)Jw^2 The angular speed w = speed/ Radius = v/R So Rotational KE = (1/2)Jw^2 = (1/2)J(v/R)^2; J is moment of inertia Now Mgh = (1/2)Mv^2 + (1/2)J(v/R)^2 => 2gh/v^2 = 1 + (J/MR^2) As v = (5gh/4)^1/2, (J/MR^2) = 2gh/v^2 - 1 => (J/MR^2) = (8gh/5gh) - 1 so (J/MR^2) = 3/5 and therefore J = (3/5)MR^2.</span>
8 0
2 years ago
Which statement is not a good practice when working inside a computer case?
lozanna [386]

Answer:

a. be sure to hold expansion cards by the edge connectors

Explanation:

Removal of loose jewelry is a good safety practice. Also not touching a microchip with a magnetized screwdriver is also a good practice.

But holding expansion cards by the edge connectors is not a good practice, so it is the odd one in the question. Therefore answer option a provides the correct and best answer to the question

3 0
2 years ago
Explain why the motto "Do whatever it takes to win!" may not be an ethical guideline to follow.
Murrr4er [49]
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2 years ago
Read 2 more answers
A cylindrical rod of steel (E = 207 GPa, 30 × 10 6 psi) having a yield strength of 310 MPa (45,000 psi) is to be subjected to a
Yanka [14]

Answer:

Diameter of the cylinder will be d=2.998\times 10^4m

Explanation:

We have given young's modulus of steel E=207GPa=207\times 10^9Pa  

Change in length \Delta l=0.38mm

Length of rod l=500mm

Load F = 11100 KN

Strain is given by strain=\frac{\Delta l}{l}=\frac{0.38}{500}=7.6\times 10^{-4}

We know that young's modulus E=\frac{stress}{strain}

So 207\times 10^9=\frac{stress}{7.6\times 10^{-4}}

stress=1573.2\times 10^{-5}N/m^2

We know that stress =\frac{force}{artea }

So 1573.2\times 10^{-5}=\frac{11100\times 1000}{area}

area=7.055\times 10^{8}m^2

So \frac{\pi }{4}d^2=7.055\times 10^{8}

d=2.998\times 10^4m          

6 0
2 years ago
Water is contained in a closed, rigid 0.2 m 3 tank at an initial pressure of 5 bar and a quality of 50%. Heat transfer occurs un
elena55 [62]

Answer:

Final mass=0.89kg

Final pressure=5.6bar

Explanation:

To find mass,m=v/v1

But v1=vf + x(vg-vf)

Vf= 0.001093m^3/kg

Vg= 0.3748m^3/kg

V1= 0.001093+0.5(0.3748-0.001093)

V1= 0.225m^3/kg

M= 0.20/0.225 =0.89kg

Final pressure will be:

V/V1= P/P1

Cross multiply

VP1=V1P

P1= 0.225×5/0.2

P1=:5.6 bar

7 0
2 years ago
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