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2 years ago

Which statements describe properties of stars check all that apply

Physics

1 answer:

VikaD [51]2 years ago

7 0

Answer:

Stars produce energy through nuclear fusion.

Stars are massive objects composed of gas.

Stars are composed primarily of hydrogen and helium.

Explanation:

Stars are massive objects that have a large gravitational field, which drives the star to contract on itself, which is why fusion occurs: in the center of the star the nuclei of atoms are already so close due to gravity and high temperatures that bind. This is what is called nuclear fusion and is the energy source of a star.

On the other hand yes, the main elements of a star are hydrogen and helium (two hydrogen nuclei fuse to make helium), this makes the star mainly a huge ball of gas so there is no solid surface where you can stand on.

And about water on a star, that is not possible. Temperatures on stars are very very high that water could not exist in a liquid form on them.

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Maverick and goose are flying a training mission in their F-14. They are flying at an altitude of 1500 m and are traveling at 68

den301095 [7]

Answer:

The bomb will remain in air for <u>17.5 s</u> before hitting the ground.

Explanation:

Given:

Initial vertical height is, $y_0=1500\ m$

Initial horizontal velocity is, $u_x=688\ m/s$

Initial vertical velocity is, $u_y=0(\textrm{Horizontal velocity only initially)}$

Let the time taken by the bomb to reach the ground be 't'.

So, consider the equation of motion of the bomb in the vertical direction.

The displacement of the bomb vertically is $S=y-y_0=0-1500=-1500\ m$

Acceleration in the vertical direction is due to gravity, $g=-9.8\ m/s^2$

Therefore, the displacement of the bomb is given as:

$S=u_yt+\frac{1}{2}gt^2\\-1500=0-\frac{1}{2}(9.8)(t^2)\\1500=4.9t^2\\t^2=\frac{1500}{4.9}\\t=\sqrt{\frac{1500}{4.9}}=17.5\ s$

So, the bomb will remain in air for 17.5 s before hitting the ground.

6 0

2 years ago

Electric charge is uniformly distributed inside a nonconducting sphere of radius 0.30 m. The electric field at a point P, which

krok68 [10]

Answer:

$E_{max}=41666.66\ N/C$

Explanation:

Given that,

The radius of sphere, r = 0.3 m

Distance from the center of the sphere to the point P, x = 0.5 m

Electric field at point P, $E_P=15000\ N/C$ (radially outward)

The maximum electric field is at the surface of the sphere. We know that the electric field is inversely proportional to the distance. So,

$\dfrac{E_{max}}{E_p}=\dfrac{0.5^2}{0.3^2}$

$\dfrac{E_{max}}{15000}=\dfrac{0.5^2}{0.3^2}$

${E_{max}}=\dfrac{0.5^2}{0.3^2}\times 15000$

$E_{max}=41666.66\ N/C$

So, the magnitude of the electric field due to this sphere is 41666.66 N/C. Hence, this is the required solution.

6 0

2 years ago

How does energy from the sun affect the motion of molecules in a gas compared to molecules in a liquid?

AnnZ [28]

Molecules in a gas move faster than in a liquid.

hope it helps.

3 0

2 years ago

Read 2 more answers

You must determine the length of a long, thin wire that is suspended from the ceiling in the atrium of a tall building. A 2.00-c

AleksAgata [21]

Answer:

Explanation:

Let L be the length of the wire.

velocity of pulse wave v = L / 24.7 x 10⁻³ = 40.48 L m /s

mass per unit length of the wire m = 14.5 x 10⁻⁶ x 10⁻³ / 2 x 10⁻² kg / m

m = 7.25 x 10⁻⁷ kg / m

Tension in the wire = Mg , M is mass hanged from lower end.

= .4 x 9.8

= 3.92 N

expression for velocity of wave in the wire

$v = \sqrt{\frac{T}{m} }$ , T is tension in the wire , m is mass per unit length of wire .

40.48 L = $\sqrt{\frac{3.92}{7.25\times10^{-7}} }$

1638.63 L² = 3.92 / (7.25 x 10⁻⁷)

L² = 3.92 x 10⁷ / (7.25 x 1638.63 )

L² = 3299.64

L = 57.44 m /s

5 0

2 years ago

The food calorie, equal to 4186J , is a measure of how much energy is released when food is metabolized by the body. A certain b

vovangra [49]

<h2>The hiker will go up to 850 m on the hill</h2>

Explanation:

The total energy gained by the hiker = 140 x 4186 J

This energy is consumed in the potential energy acquired , while climbing up the hill.

The potential energy P.E = mass of hiker x acceleration due to gravity x height

Thus

140 x 4186 = 69 x 10 x h

or h = $\frac{4186x140}{69x10}$ = 850 m

If the 20% of the total energy is used

the height h₀ = $\frac{0.2x4186x140}{69x10}$ = 170 m

5 0

2 years ago