Ask question

Ask question

All categories

2 years ago

6

At a certain location, a gravitational force with a magnitude of 350 newtons acts on a 70.-kilogram astronaut. What is the magni

tude of the gravitational field strength at this location? (1) 0.20 kg/N (2) 9.8 m/s2 (3) 5.0 N/kg (4) 25 000 Nkg

1 answer:

creativ13 [48]2 years ago

6 0

Answer:

3. 5.0N/kg

Explanation:

Gravitational field strength = gravitational force/mass of astronaut = 350N/70kg = 5.0N/kg

You might be interested in

A gas laser has a cavity length of 1/3 m and a single oscillation frequency of 9.0 x 1014 Hz. What is the cavity mode number?

Eddi Din [679]

Answer:

2 × 10⁶

Explanation:

Data provided in the question:

Cavity length, L = $\frac{1}{3}m$

Oscillation frequency, $f_m$ = 9.0 × 10¹⁴ Hz

Now,

we know,

$f_m=\frac{c}{\lambda_m}$

here,

c is the speed of light = 3 × 10⁸ m/s

$\lambda_m$ = Wavelength of mode m inside the laser cavity

m is the cavity mode number

Thus,

$9.0\times10^{14}=\frac{3\times10^8}{\lambda_m}$

or

$\lambda_m$ = $\frac{1}{3}$ × 10⁻⁶

Also,

$m\lambda_m = 2L$

Therefore,

m × $\frac{1}{3}$ × 10⁻⁶ = 2 × $\frac{1}{3}$

or

m = 2 × 10⁶

5 0

2 years ago

Gold and silicon are mutually insoluble in the solid state and form a eutectic system with a eutectic temperature of 636 k and a

kupik [55]

Yupp its c because my dad farted

3 0

2 years ago

A uniform sphere with mass M and radius R is rotating with angular speed ω1 about a frictionless axle along a diameter of the sp

liq [111]

Answer:

$W_2=\sqrt{\frac{3}{5} }W_1$

Explanation:

For the first ball, the moment of inertia and the kinetic energy is:

$I_1 =\frac{2}{5}MR^2$

$K_1 = \frac{1}{2}IW_1^2$

So, replacing, we get that:

$K_1 = \frac{1}{2}(\frac{2}{5}MR^2)W_1^2$

At the same way, the moment of inertia and kinetic energy for second ball is:

$I_2 =\frac{2}{3}MR^2$

$K_2 = \frac{1}{2}IW_2^2$

So:

$K_2 = \frac{1}{2}(\frac{2}{3}MR^2)W_2^2$

Then, $K_2$ is equal to $K_1$ , so:

$K_2 = K_1$

$\frac{1}{2}(\frac{2}{3}MR^2)W_2^2 = \frac{1}{2}(\frac{2}{5}MR^2)W_1^2$

$\frac{1}{3}MR^2W_2^2 = \frac{1}{5}MR^2W_1^2$

$\frac{1}{3}W_2^2 = \frac{1}{5}W_1^2$

Finally, solving for $W_2$ , we get:

$W_2=\sqrt{\frac{3}{5} }W_1$

5 0

2 years ago

Which best explains why infrared waves are ineffective for treating cancer ?

Natali5045456 [20]

If it is a multiple choice question is C. Infrared waves do not carry enough energy to kill cancerous cells.

8 0

2 years ago

Read 2 more answers

Find the time t1 it takes to accelerate the flywheel to ω1 if the angular acceleration is α. express your answer in terms of ω1

VMariaS [17]

T1 = ω1/α.............

3 0

2 years ago

Read 2 more answers