Ask question

Ask question

All categories

2 years ago

14

Ariel dropped a golf ball from her second story window. The ball starts from rest and hits the sidewalk 3.5 s later with a veloc

ity of 14.7 m/s. Find the average acceleration of the golf ball.

1 answer:

Aleks [24]2 years ago

4 0

Answer:

By using the acceleration formula,

$a = \frac{v - u}{t}$

$a = \frac{14.7 - 0}{3.5}$

$a = 4.2m \: s ^{ - 2}$

You might be interested in

What is the longest wavelength light capable of ionizing a hydrogen atom in the ground state?

Sindrei [870]

Answer:

$9.12\cdot 10^{-8} m$

Explanation:

The energy needed to ionize a hydrogen atom in the ground state is:

$E=13.6 eV= 2.18\cdot 10^{-18}J$

The energy of the photon is related to the wavelength by

$E=\frac{hc}{\lambda}$

where

h is the Planck constant

c is the speed of light

$\lambda$ is the wavelength

Solving the formula for the wavelength, we find

$\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{2.18\cdot 10^{-18}J}=9.12\cdot 10^{-8} m$

7 0

2 years ago

For each property listed, identify the type of element it describes. Very good electrical conductivity: Amphoteric, able to form

kow [346]

The elements that is very good in electrical conductivity are gold and copper: elements that is amphoteric are copper, zinc, tin, lead, aluminum and beryllium: elements that is gaseous at room temperature are hydrogen, nitrogen, oxygen, fluorine and chlorine: elements that is solid at room temperature are all metal except mercury and perhaps some unseen radioactive elements. Lastly, elements that is brittle are hydrogen, carbon, nitrogen, oxygen, phosphorus, sulfur and selenium

4 0

2 years ago

Read 2 more answers

A 1.2 kg ball moving due east at 40 m/s strikes a stationary 6.0 kg object. The 1.2 kg ball rebounds to the west at 25 m/s. What

RSB [31]

V_2' = v_1 + v_1'
So v_2' = 40 + -25
We have set east to be + and west -
Which gives us 15 m/s. So thats how fast the 6 kg object is going.
This is true for an elastic collision.

4 0

2 years ago

Your 64-cm-diameter car tire is rotating at 3.5 rev/s when suddenly you press down hard on the accelerator. After traveling 200

andreyandreev [35.5K]

Answer: angular acceleration = 0.748rad/s²

Explanation: according to the question, our answer needs to be in rad/s², thus all units in rev/s will be converted to rad/s

Assuming the motion of the object is of a constant angular acceleration, then newton's laws of motion is applicable.

The formulae below is used

v² = u² + 2αθ

v = final angular speed =6rev/s = 6*2π = 12π rad/s

u =initial angular speed =3.5rev/s = 3.5 *2π = 7π rad/s

Note 1 rev = 2π rad.

α = angular acceleration.

θ = angular displacement.

Diameter = 64cm = 0.64m, radius = 64/2 = 32cm = 0.32m

The angular displacement can be gotten using the formulae below

S = rθ, where s= linear distance covered = 200m, r = radius = 0.32m

θ = S/r = 200/0.32=625 rad.

By substituting the parameter we have that

(12π)² = (7π)² + 2α(625)

1421.22 = 486.31 + 1250α

1421.22 - 486.31 = 1250α

934.91 = 1250α

α = 934.91/1250

α= 0.748 rad/s²

4 0

2 years ago

You are given a vector in the xy plane that has a magnitude of 90.0 units and, a y component of -41.0 units. Assuming the x comp

zepelin [54]

In your question where as the given vector in the xy plane that has a magnitude of 90 units and a,y component of -41 units. So the vector V, base on my calculation and understanding in the problem, the value if it is (<span>8.88, 41</span>)

4 0

2 years ago

Read 2 more answers