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2 years ago

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An elevator has a weight of 14,700 N and has an acceleration of –0.30 m/s2. The free-body diagram shows the forces acting on the

elevator.
A free body diagram with 2 force vectors. One vector is pointing up, labeled F Subscript t Baseline. The second vector is shorter pointing down, labeled F Subscript g Baseline.
To the nearest whole number, what is the force of tension, Ft, acting on the elevator?

2 answers:

attashe74 [19]2 years ago

6 0

Answer:

14,250 N

Explanation:

Weight = 14,700 N

Acceleration = -0.30m/s²

$Acceleration = -0.30m/s2[tex]Weight=Fg\\\\Fg=mg\\\\Fg=14,700N\\m=?\\g=9.8m/s^{2} \\\\14,700N=m(9.8m/s^{2} ) \\\\14,700N/9.8ms^{2} =1500kg(mass)\\\\m=1500kg\\a=-0.30m/s^{2}\\\\f=ma\\f=(1500kg)(-0.30m/s^{2} )\\=-450N (net force)\\\\-450N=-14,700N+(Ft)\\14,250N=Ft$

qwelly [4]2 years ago

4 0

14250. I just took it

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