Answer:
2.98 second
Explanation:
The severity index is defined by :
a is dimensionless constant that equals the number of multiples of g
Conditions are given as :
Initial velocity, u = 0
Acceleration, a = 34 m/s²
Final velocity, v = 16.4 km/h = 4.56 m/s
We can find t from the above data as follows :
As a is the acceleration that is multiple of g.
So,
So,
Severity index,
Hence, the severity index for the collision is 2.98 seconds.
Answer:
ΔE = 8.77 × 10¹¹ J
Explanation:
given,
²¹⁴₈₄Po -----> ²¹⁰₈₂Pb + 42 He
Atomic masses: Pb-210 = 209.98284 amu
Po-214 = 213.99519 amu
He-4 = 4.00260 amu
1 kg = 6.022 × 10²⁶ amu;
NA = 6.022 × 10²³ mol⁻¹
c = 2.99792458 × 10⁸ m/s
energy of molecule using equation
ΔE = Δm c²
Δm is mass difference and c is speed of light
Δm = 209.98284 + 4.00260 - 213.99519
Δm = - 0.00975 amu
1 amu = 1.66 x 10⁻²⁷ kg
- 0.00975 amu = - 0.00975 x 1.66 x 10⁻²⁷ Kg
= -0.016185 x 10⁻²⁷ Kg
total mass = 6.022 × 10²³ x -0.016185 x 10⁻²⁷
= -0.097467 x 10⁻⁴ Kg
ΔE = -(0.097467 x 10⁻⁴) (3 x 10^8)²
ΔE = - 8.77 × 10¹¹
ΔE = 8.77 × 10¹¹ J
<span>Bit level for a CCD (Charged coupled device) with a greatest possible pixel value of 4095:The relationship between the bit level and pixel value is given as:pixel value = 2^bit level.Most charged coupled devices (CCDs) have 8-bit, 16-bit, 32-bit levels.Using simple mathematics, we can see that 2^12 = 4096.Since the maximum number of pixels is 4095, the bit level is 12., i.e. the CCD has 12-bit level.</span>
Answer:
It is a superordinate goal because both teams could have helped with the task.
Explanation:
If both teams pushed then they could have made it happened
The question is incomplete, the concentration of qam and humulin is not given unless R is used concentration
Complete question:
A physician orders Humulin 50/50 44 units and Humulin N 40 units qam and Humulin R 35 units ac evening meal subcutaneously. How many total units of insulin are administered each morning?
Answer:
the total units of insulin admistered each morning
= 22 units of qam and humulin
Explanation:
given
44 units and Humnlin N
with concentration 50/100 = 1/2 = 0.5
∴ 44 × 0.5 ≈ 22 units in the morning
regular insulin administered each day
(22 + 35)units of qam and humulin
= 57units
