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2 years ago

A car has a mass of 1.00 × 103 kilograms, and it has an acceleration of 4.5 meters/second2. What is the net force on the car

Physics

1 answer:

Novay_Z [31]2 years ago

0 0

Answer:

$4.5 *10^{3}\ kgm/s^{2}$

Explanation:

Given:

$Mass= 1.00 * 10^{3} \ kilograms,\\Acceleration =4.5\ meters/second^{2}$

As we know that

Force=Mass * Acceleration

Putting the value of mass and Acceleration we get ,

$Force\ = \ 1.00 * 10^{3} * 4.5\ m/s^{2}$

$Force\ =4.5 * \ 10^{3} \ kgm/s^{2}$

Therefore Net force is : $4.5 *10^{3}\ kgm/s^{2}$

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Leona [35]

Answer:

Explanation:

Given

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$x=4\times \sqrt{2}-\frac{2}{3}\times 2\sqrt{2}$

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7 0

1 year ago

A boy is pulling a load of 150N with a string inclined at an angle 30 to the horizontal if the tension of string is 105N the for

Lorico [155]

The force tending to lift the load (vertical force) is equal to <u>22.5N.</u>

Why?

Since the boy is pulling a load (150N) with a string inclined at an angle of 30° to the horizontal, the total force will have two components (horizontal and vertical component), but we need to consider the given information about the tension of the string which is equal to 105N.

We can calculate the vertical force using the following formula:

$VerticalForce=Force*Sin(30\° )=(BoysForce-StringForce)*\frac{1}{2}\\\\VerticalForce=(150N-105N)*\frac{1}{2}=VerticalForce=45N*\frac{1}{2}=22.5N$

Hence, we can see that <u>the force tending to lift the load</u> off the ground (vertical force) is equal to <u>22.5N.</u>

Have a nice day!

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2 years ago

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2 years ago

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oee [108]

Answer:

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2 years ago

Suppose the truck that’s transporting the box In Example 6.10 (p. 150) is driving at a constant speed and then brakes and slows

Scorpion4ik [409]

Answer:

Friction acts in the opposite direction to the motion of the truck and box.

Explanation:

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Now when the truck is applying brakes, only it itself is being slowed down. Since the box is slowing down with the truck, we can conclude that it is friction that slows it down.

The box in the question tries to maintains its velocity forward when the brakes are applied. We can think of this as the box exerting a positive force relative to the truck when the brakes are applied. When we imagine this, we can also figure out where the static friction will act to stop this positive force. Friction will act in the negative direction. Or in other words, friction will act in the opposite direction to the motion of the truck and box. This explains why the box slows down with the truck, as friction acts to stop its motion.

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