What is NOT one of the three primary resources that families have to reach financial goals? It is c) education
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As far as the field goes, the two charges opposite each other cancel!
So E = kQ / d² = k * Q / (d/√2)² = 2*k*Q / d² ◄
and since k = 8.99e9N·m²/C²,
E = 1.789e10N·m²/C² * Q / d² </span>
Answer:

29010.53917 m
Explanation:
= Density of asteroid = 2 g/cm³
V = Volume
d = Diameter = 10 km
r = Radius = 
v = Velocity = 11 km/s
= Heat vaporization of water = 
= Change in temperature = 100-20
Mass is given by

The kinetic energy is

Heat is given by

Mass of water is 
Volume is 
Amount of water is 
If it were a cube

The height of the water would be 29010.53917 m
Answer:
Part(a): The angular acceleration is
.
Part(b): The angular displacement is
.
Explanation:
Part(a):
If
be the initial angular speed, final angular speed and angular acceleration of the centrifuge respectively, then from rotational kinematic equation, we can write

where '
' is the time taken by the centrifuge to increase its angular speed.
Given,
,
and
. From equation (
), the angular acceleration is given by

Part(b):
Also the angular displacement (
) can be written as

Answer:
The ball was in air for 3.896 s
Explanation:
given,
g = 9.8 m/s², acceleration due to gravity,
If the launch angle is 45°, the horizontal range will be maximum.
The horizontal and vertical launch velocities are equal, and each is equal to
v_h = v cos θ
v_h = 27 × cos 45°
= 19.09 m/s.
The time to attain maximum height is one half of the time of flight.
v = u + at ∵ v = 0 (max. height)
19.09 - 9.8 t₁ = 0
t₁ = 1.948 s
The time of flight is twice of the maximum height time
2 t₁ = 3.896 s
The horizontal distance traveled is
D = v × t
D = 3.896×19.09
= 74.375 m
The ball was in air for 3.896 s