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worty [1.4K]
2 years ago
9

A 60 kg student in a rowboat on a still lake decides to dive off the back of the boat. The studen'ts horizontal aceleration is 2

.0 m/s2 while in contact with the boat. What horizontal force does the student exert on the boat?
a 30N toward the back of the boat
b 120 n toward the front of the boat
c 30 n toward the front of the boat
d 120 n toward the back of the boat
Physics
1 answer:
TiliK225 [7]2 years ago
4 0
As per the third law of Newton, the force exerted by the boat over the student is equal in magnitude to the force that the student exerted on the boat.

So, calculate the force on the student using the second law of Newton, Force = mass * acceleration.

Force on the student = 60 kg * 2.0 m/s^2 = 120 N.

=> horizontal force exerted by the student on the boat = 120 N

Answer: option d. 120 N. toward the back of the boat.

Of course it is toward the back because that is where the student jumped from..
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Answer:

W ≈ 5.9 × 10^{2} J

Hence, option (c) is correct.

Given:

mass of box = 6 kg

Displacement of box = 10 m

To find:

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Formula used:

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Work done is equal to change is potential energy,

W = m g h

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m = mass of the box

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To develop this problem we will proceed to convert all units previously given to the international system for which we have to:

140 lb = 63.5 kg \rightarrow 63.5kg (9.8m/s) =622.3 N

120 lb = 54.4 kg \rightarrow 54.4kg (9.8m/s)= 533 N

170 lb = 77.1 kg \rightarrow 77.1 kg (9.8m/s) =756 N

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F = 756 - 622.3

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Through the Newtonian relationship of the Force we have to:

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PART B) For the maximum magnitude of the acceleration downward we have that:

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