In a pith ball experiment, the two pith balls are at rest. The magnitude of the tension in each string is |T|=0.55N, and the ang
1 answer:
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Explanation:
(a) It is given that two-third of weight is over the drive wheels. So, mathematically, w = .
Hence, maximum force is expressed as follows.
Hence, the maximum acceleration is calculated as follows.
=
= 6.53
Hence, the maximum acceleration of the Porsche on a concrete surface where μs = 1 is 6.53 .
(b) Since, 30% of the power is lost in the drive train. So, the new power is 70% of .
That is, new power =
Now, the expression for power in terms of force and velocity is as follows.
P =
Therefore, speed of the Porsche at maximum power output is as follows.
=
= 11.568 m/s
= 11.57 m/s
Therefore, speed of the Porsche at maximum power output is 11.57 m/s.
(c) The time taken will be calculated as follows.
time =
=
= 1.77 s
Therefore, the Porsche takes 1.77 sec until it reaches the maximum power output.
Answer:
230
Explanation:
= Rotational speed = 3600 rad/s
I = Moment of inertia = 6 kgm²
m = Mass of flywheel = 1500 kg
v = Velocity = 15 m/s
The kinetic energy of flywheel is given by
Energy used in one acceleration
Number of accelerations would be given by
So the number of complete accelerations is 230